Let x and y be width and length of the plot to be fenced. Therefore,
Area (A) = xy m^2
If the side bordering the river is x, then
Circumference (C) = 8500 = x+2y => x = 8500-2y
Substituting for w in the equation for A;
A = (8500-2y)y = 8500y -2y^2
For maximum area, derivative of A with respect to y is 0. That is;
dA/dy = 0 = 8500 -4y => 4y = 8500 => y = 8500/4 = 2125 m
And, x = 8500-2y = 8500 -2*2125 = 4250 m
Therefore,
One side = 4,250 m and second side = 2,125 m.
Largest area, A = 4250*2125 = 9,031,250 m^2
Answer:
6 pizzas
Step-by-step explanation:
At least 10 and fewer than 20 makes it 10-19
So,
10-19 => 6 pizzas
6 pizzas have at least 10 pieces of pepperoni but fewer than 20 pieces of pepperoni.
The coordinates of point P would be (2.6, 1.6).
The ratio of the sides being 3:7 means that the segment JP would be 3/10 of the total and PK would be 7/10 of the segment.
The slope of JK is given by finding the rise/run; in this case that is 4/2=2. Since JP is 3/10 of the segment, we add 3/10 of the rise to the x-coordinate and 3/10 of the run to the y-coordinate:
(3/10(2)+2, 3/10(2)+1)
=(6/10+2, 6/10+1)
=(2.6, 1.6)
Y=6 x=2/3
y=12 x=?
6*2=12, 2/3*2=?
?=2*2/3
?=1 and 1/3
Answer:
x-120=899
Step-by-step explanation:
(x=1019)
