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trapecia [35]
3 years ago
8

Bismuth oxide reacts with carbon to form bismuth metal: bi2o3(s) + 3c(s) → 2bi(s) + 3co(g) when 689 g of bi2o3 reacts with exces

s carbon, (a) how many moles of bi form? 2.957 mol bi (b) how many grams of co form? g co

Chemistry
2 answers:
ExtremeBDS [4]3 years ago
8 0
Using the answer from the first part, we know that 2.957 moles of bismuth have formed. Moreover, the molar ratio between bismuth and carbon monoxide is:

2 : 3

Using the method of ratios,

2 : 3
2.957 : CO

CO = (3 * 2.957) / 2
CO = 4.4355

4.436 moles of carbon monoxide will be formed
Hunter-Best [27]3 years ago
7 0

CO mass = 4,435. 18 = 79,839 grams

Stokiometry in Chemistry learns about chemical reactions mainly emphasizing quantitative, such as calculation of volume, mass, number, which is related to the number of ions, molecules, elements etc.

In chemical calculations, the reaction can be determined, the number of substances that can be expressed in units of mass, volume, mole, or determine a chemical formula, for example the substance level or molecular formula of hydrate.

In stockiometry therein includes

relative atomic mass (Ar) and relative molecular mass (Mr)

Mr. AxBy = (x.Ar A + y. Ar B)

Reactions that occur:

Bi₂O₃ (s) + 3C (s) → 2Bi (s) + 3CO (g)

  • We specify mole Bi₂O₃

Mr Bi₂O₃ = 2. ar bi + 3. Ar O

Mr Bi₂O₃ = 2. 209 + 3. 16

Mr. Bi₂O₃= 466

mole Bi₂O₃ = gram / Mr

mole = 689/466

mole 1.4785

  • A. Comparison of Bi reaction coefficients: Bi₂O₃ = 1: 2, then Bi moles = 2. 1,4785 = 2, 957

Comparison of Bi reaction coefficients:  Bi₂O₃  = 1: 2,

  • B. While the number of moles CO = 3 x 1.4785 = 4,435

Mr. CO = 12 + 16 = 18

mass CO = mole. Mr

CO mass = 4,435. 18 = 79,839 grams

<h3><em>Learn more </em></h3>

how many moles of water you can produce

brainly.com/question/1405182

Excess reactant

brainly.com/question/6857557

The percentage yield

brainly.com/question/12044319

Limiting reactant

brainly.com/question/5798341

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(i) We start by calculating the mass of sugar in the solution:

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(ii) We use the following reasoning:

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If 12.4 mol of Ne gas occupies 122.8 L, how many mol of Ne would occupy 339.2 L under the same temperature and pressure? Record
8090 [49]

Answer:

3.43×10¹ mol

Explanation:

Given data:

Initial number of  moles = 12.4 mol

Initial volume = 122.8 L

Final number of moles = ?

Final volume = 339.2 L

Solution:

The number of moles and volume are directly proportional to each other at same temperature and pressure.

V₁/n₁  =  V₂/n₂

122.8 L/ 12.4 mol  =  339.2 L / n₂

n₂ = 339.2 L× 12.4 mol  / 122.8 L

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n₂ = 34.3mol

In scientific notation:

3.43×10¹ mol

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3 years ago
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