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2 years ago

Determine the mass fraction of iron in its compounds:

Chemistry

1 answer:

Shkiper50 [21]2 years ago

7 0

Explanation:

We have a molecule composed of 3" role="presentation" style="box-sizing: inherit; margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; one; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">33 iron atoms, and 4" role="presentation" style="box-sizing: inherit; margin: 0px; padding: 0px; border: p; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">44 atoms of another element. We are given the following information: it has 2.36 g" role="presentation" style="box-sizing: inherit; margin: 0px; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">2.36 g2.36 g of iron for 3.26 g" role="presentation" style="box-sizing: inherit; margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: -wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">3.26 g3.26 g of molecule.

I want to find the molar mass of the compound, I have tried so far:

m=3.26 g=0.00326 kg" role="presentation" style="box-sizing: inherit; margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; font-stretch: inherit; line-height: normal; font-family: inherit; font-size: 15px; vertical-align: baseline; display: inline; text-indent: 0px; text-align: center; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">m=3.26 g=0.00326 kgm=3.26 g=0.00326 kg

Since it has 3" role="presentation" style="box-sizing: inherit; margin: 0px; padding: 0px; nt-variant: inherit; font-weight: normal; font-stretch: inherit; line-height: normal; font-family: inherit; font-size: 15px; vertical-align: baseline; display: inline; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">FeFe and 4" role="presentation" style="box-sizing: inherit; margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; font-stretch: inherit; line-height: normal; ; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">44 atoms of an unknown substance, therefore:

3+4=7 atoms,1 mol=6.022⋅1023 atoms76.022⋅1023=1.16⋅10−23" role="presentation" style="box-sizing: inherit; margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: : ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; width: 10000em !important; ; font-family: inherit; eight: none; min-width: 0px; min-height: 0px; position: relative;">0.003260.00326 by 1.16⋅10−23" role="presentation"; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">1.16⋅10−231.16⋅10−23 and I obtained 2.79429⋅1019" role="presentation" style="box-sizing: inherit; margin: 0px; padding: 0px; border: 0px; f inherit; font-size: 15px; vertical-align: baseline; display: inline; text-indent: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">2.79429⋅10

IT'S TOTAL ANSWER OF ITS AND THIS QUESTION IS IN MATHEMATION FINAL EXAM. PLEASE GIVE❤ AND MARK ME A BRAINLIST

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Option B is correct

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Answer:

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44 g of CO₂ contains 12 g of C

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3 years ago

A chemist adds 1.80L of a 1.1/molL aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum ch

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Answer:

2000 millimoles of AlCl₃

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 1.8 L

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Millmole of AlCl₃ =?

Next, we shall determine the number of mole of AlCl₃ in the solution.

This can be obtained as follow:

Volume of solution = 1.8 L

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Number of mole of AlCl₃ =?

Molarity = mole /Volume

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Number of mole of AlCl₃ = 1.1 × 1.8

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3 years ago

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Answer:

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