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goblinko [34]
3 years ago
12

The probability?????????????????

Chemistry
1 answer:
olga55 [171]3 years ago
7 0
Answer: 4/20

Explanation:
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I need number 5,6 please thanks
bulgar [2K]
5. b is the right answer

6. c is the right answer
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3 years ago
C(S)+O2(g)-->CO2(g)
soldi70 [24.7K]

<u>Answer:</u> The correct answer is 1.18 g.

<u>Explanation:</u>

We are given a chemical equation:

C(S)+O2(g)\rightarrow CO_2(g)

We know that at STP conditions:

22.4L of volume is occupied by 1 mole of a gas.

So, 2.21L of carbon dioxide is occupied by = \frac{1}{22.4L}\times 2.21L=0.0986mol of carbon dioxide gas.

By Stoichiometry of the above reaction:

1 mole of carbon dioxide gas is produced by 1 mole of carbon

So, 0.0986 moles of carbon dioxide is produced by = \frac{1}{1}\times 0.0986=0.0986mol of carbon.

Now, to calculate the mass of carbon, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of carbon = 0.0986 mol

Molar mass of carbon = 12 g/mol

Putting values in above equation, we get:

0.0986mol=\frac{\text{Mass of carbon}}{12g/mol}\\\\\text{Mass of carbon}=1.18g

Hence, the correct answer is 1.18 g.

3 0
3 years ago
Read 2 more answers
What is the maximum mass of P2I4 that can be prepared from 8.80g of P4O6 and 12.37g of iodine according to the reaction:
Dvinal [7]
The balanced chemical reaction would be as follows:

<span>5P4O6 +8I2 ---> 4P2I4 +3P4O10

We are given the amount of reactants used for the reaction. We first need to determine the limiting reactant from the given amounts. We do as follows:

8.80 g P4O6 (1 mol / </span><span>219.88 g) = 0.04 mol P4O6
12.37 g I2 ( 1 mol / </span><span>253.809 g ) = 0.05 mol I2

Therefore, the limiting reactant is iodine since less it is being consumed completely in the reaction. We calculate the amount of P2I4 prepared as follows:

0.05 mol I2 ( 4 mol P2I4 / 8 mol I2 ) (</span><span>569.57 g / 1 mol) = 14.24 g P2I4</span>
8 0
3 years ago
Read 2 more answers
The most important ore of aluminum is _____ show the chemical formula ​.​
3241004551 [841]

Answer:

The most important ore of aluminum is<u> Bauxite.</u>

And its chemical formula is Al_2O_3.2H_2O.

Explanation:

Bauxite is the most important ore of Aluminium from which Aluminium is extracted. Bauxite is a rock and composed of Aluminium bearing mineral.

And its chemical formula is Al_2O_3.2H_2O.

It contains Gibbsite, Bohmite and Diaspore along with iron.

It is a soft material with somewhat white to grey to reddish brown in colour.

It has an earthy lustre and low specific gravity.

<u />

5 0
3 years ago
Use the conversion factor 1 amu = 1.66054× 10–24 g to answer the following questions. a) 1.67 x 10-24 g of neurons is how many (
sergij07 [2.7K]
You can use the mass of neuron divided by the mass of conversion factor: 1.67*10^(-25)/(1.66054*10^(-24))≈1 amu. So the answer is 1 amu. 
7 0
3 years ago
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