The mass of magnesium should be less than 0.09g to enable a faster reaction rate. Magnesium reacts to form a white coating around it which stops the reaction. The lesser the gram the faster the reaction before the coating is formed. It is also advisable to use magnesium fillings to increase the rate of reaction.
E has indeed the lowest freezing point.
The second volume : 42.2 L
<h3>Further explanation</h3>
Given
51.7 L at 27 C and 90.9 KPa
Required
The second volume
Solution
STP = P₂=1 atm, T₂=273 K
T₁ = 27 + 273 = 300 K
P₁ = 90.9 kPa = 0,897 atm
Use combine gas law :
P₁V₁/T₁ = P₂V₂/T₂
Input the value :
0.897 x 51.7/300 = 1 x V₂/273
V₂= 42.20 L
Answer:
191.11 grams of oxygen gas should be produced.
Explanation:
The balanced reaction is:
2 Al₂O₃ → 4 Al + 3 O₂
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Al₂O₃: 2 moles
- Al: 4 moles
- O₂: 3 moles
Being the molar mass of each compound:
- Al₂O₃: 102 g/mole
- Al: 27 g/mole
- O₂: 32 g/mole
By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- Al₂O₃: 2 moles* 102 g/mole= 204 grams
- Al: 4 moles* 27 g/mole= 108 grams
- O₂: 3 moles* 32 g/mole= 96 grams
Then you can apply the following rule of three: if by stoichiometry 108 grams of aluminum are produced along with 96 grams of oxygen, 215 grams of aluminum are produced along with how much mass of oxygen?
mass of oxygen= 191.11 grams
<u><em>191.11 grams of oxygen gas should be produced.</em></u>