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shtirl [24]
4 years ago
7

Which electron configuration represents an atom of lithium in an excited state?

Chemistry
1 answer:
creativ13 [48]4 years ago
8 0
There are many options, such as: 2-0-1, 1-1-1, 0-1-2, but they must all equal 3 electrons in total
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Para solucionar el ejercicio primero se debe conocer el número atómico de los elementos para determinar cuantos electrones tiene
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Answer:

El número atómico se refiere al número de protones o electrones de un átomo.

Explicación:

El número atómico se refiere a la cantidad de protones o la cantidad de electrones que giran alrededor de las capas u órbita de un átomo, por lo que el número atómico 7 representa que el átomo tiene 7 electrones o protones mientras que, por otro lado, el número atómico 17 muestra el número de electrones o protón. Solo hay dos electrones que entran en la primera órbita y en el resto de las capas tiene espacio para 8 electrones por lo que los átomos pierden o agregan electrones en su capa más externa para obtener estabilidad.

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Can we move only one electron from its orbit to another orbit of lower energy without moving other electrons of the atom? well i
Mrac [35]
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7 0
3 years ago
Calculate ℰ° values for the galvanic cells described below. (a) cr3+(aq) + cl2(g) equilibrium reaction arrow cr2o72-(aq) + cl -(
Ad libitum [116K]

Answer:

\boxed{\text{(a) 0.00 V; (b) 0.424 V}}

Explanation:

We must look up the standard reduction potentials for the half-reactions.

                                                                  <u>   ℰ°     </u>

Cr₂O₇²⁻ + 14H⁺ + 6e⁻ ⇌ 2Cr³⁺ + 7H₂O     1.36

Cl₂ + 2e⁻ ⇌ 2Cl⁻                                       1.35827

2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O             1.195

Fe³⁺ + e⁻ ⇌ Fe²⁺                                      0.771

(a) Cr³⁺/Cl₂

We reverse the sign of ℰ° for the oxidation half-reaction. Then we add the two half-reactions and their ℰ° values.

                                                                               <u>   ℰ°/V     </u>

2Cr³⁺ + 7H₂O ⇌ Cr₂O₇²⁻ + 14H⁺ + 6e⁻                  -1.36

<u>Cl₂ + 2e⁻ ⇌ 2Cl⁻                                                </u>     <u>1.358 27 </u>

2Cr³⁺ + 3Cl₂ + 7H₂O ⇌ Cr₂O₇²⁻  + 6Cl⁻ + 14H⁺     0.00

(b) Fe²⁺/IO₃⁻

                                                                           <u> ℰ°/V </u>

Fe²⁺ ⇌ Fe³⁺ + e⁻                                                -0.771

<u>2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O                   </u>   <u>  1.195 </u>

10Fe²⁺ + 2IO₃⁻ + 12H⁺ ⇌ 10Fe³⁺ + I₂ + 6H₂O     0.424

The ℰ° values for the cells are \boxed{\textbf{(a) 0.00 V; (b) 0.424 V}}

4 0
4 years ago
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