Pressure since pressure is defined as force per unit area and the molecules exert a force on the walls of the container when they bombard it
Answer:
0.38
Explanation:
As you go from 0 % hexane (χ = 0) to 100 % hexane (χ = 1), the refractive index decreases from 1.407 to 1.375, a decrease of 0.032.
From 1.407 to 1.3948, the decrease is 0.0122
.
That is 0.0122/0.032 = 0.38 of the distance from χ = 0 to χ = 1.
The mole fraction of hexane is 0.38.
The diagram below is a plot of refractive index vs. the mole fraction of hexane. It shows that the refractive index drops to 1.3948 when χ = 0.38.
Answer:
4.12 moles
Explanation:
We can solve this problem with the Ideal Gases Law.
P . V = n . R . T
In our first case we have:
P = 2.3 atm
V = 32.8 L
n = 2.98 moles
T → 35°C + 273 = 308K
Let's replace data for the second case:
2.3 atm . 45.3L = n . 0.082 . 308K
n = (2.3 atm . 45.3L) / (0.082 L.atm/mol.K . 308K)
n = 4.12 moles