Answer:
The bismuth sample.
Explanation:
The specific heat 
of a substance (might not be a metal) is the amount of heat required for heating a unit mass of this substance by unit temperature (e.g., 
.) The formula for specific heat is:
,
where
is the amount of heat supplied.
is the mass of the sample. 
is the increase in temperature.
In this question, the value of (amount of heat supplied to the metal) and (mass of the metal sample) are the same for all four metals. To find (change in temperature,) rearrange the equation:
,
.
In other words, the change in temperature of the sample, can be expressed as a fraction. Additionally, the specific heat of sample, , is in the denominator of that fraction. Hence, the value of the fraction would be the largest for sample with the smallest specific heat.
Make sure that all the specific heat values are in the same unit. Find the one with the smallest specific heat: bismuth (
.) That sample would have the greatest increase in temperature. Since all six samples started at the same temperature, the bismuth sample would also have the highest final temperature.
Answer:
1461.7 g of AgI
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI
Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:
Mole of AgI = 6.22 moles
Molar mass of AgI = 108 + 127
= 235 g/mol
Mass of AgI =?
Mass = mole × molar mass
Mass of AgI = 6.22 × 235
Mass of AgI = 1461.7 g
Therefore, 1461.7 g of AgI were obtained from the reaction.
False because you have to take it out and do it right
Answer
raise/lower temp of certain ecosystems. Bring new predators/prey. Erode surrounding environment
Explanation:
