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2 years ago

5

Help pls?

1 answer:

zimovet [89]2 years ago

4 0

Answer:

Look up the different clauses of the variables and write them down. Trust me it helps alit to have them infrount if you. If u have a question about what one if the things u have to identify is. Please tell me. :D

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Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

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2 years ago

The lighthouse was moved 230 feet inland at a rate of 40 feet per hour. How many hours did it take to move the lighthouse? What

Aleks04 [339]

Answer:

5.75

Step-by-step explanation:

4) 230 ÷ 40 = 5.75

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2 years ago

A bakery is making whole-wheat bread and apple bran muffins. For each batch of break they make $35 profit. For each batch of muf

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Answer:

Graph the linear equation.

Step-by-step explanation:

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1 year ago

What is the surface area of this right rectangular prism?

vagabundo [1.1K]

Answer:

A≈32 $\frac{3}{10}$ ft²

--

To find the surface area of a right rectangular prism you must use this formula A=2(wl+hl+hw)

Then plug in your variebles

A=2( 1.33*1.5+5+1.5+5+1.33)

This comes out to be A≈32 $\frac{3}{10}$

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1 year ago

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skelet666 [1.2K]

Answer:it’s the third one

Step-by-step explanation:

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2 years ago

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