Answer: The value of k is 0.09.
Step-by-step explanation:
Since we have given that

Here, k is the rate ,
t is the time,
In 2004, the whooping cranes tallied 213 birds,
So, P(t)=213
It is 19 greater than 2003,
So, P(0)=213-19=194
So, substitute all the values in given expression:

Hence, the value of k is 0.09.
Take option 2.
Let n=2^30
Then:
ln n=ln 2^30=30 ln 2
ln n=20.8
n=e^20.8, or 1,073,741,824
1073741824 x.01=$10,737,418.24 due in salary at the end of the first month!!!!!
You have to test dp/dt between these intervals
(-inf,2)
(2,10)
(10,inf)
if dp/dt is positive then the population is increasing with respect to time in that interval
Answer:
a)
b) 


And we have the following table:
X | 0 | 1 | 2
P(X) | 0.25 | 0.5 | 0.25
Step-by-step explanation:
Let's define first some notation
H= represent a head for the coin tossed
T= represent tails for the coin tossed
We are going to toss a coin 2 times so then the size of the sample size is 
a. What is the sample space for this chance experiment?
The sampling space on this case is given by:
b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.
The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:



And we have the following table:
X | 0 | 1 | 2
P(X) | 0.25 | 0.5 | 0.25
The median for city A is 4 and the median for city B is 5.25.