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2 years ago

What is the fastest 10 km in 0.5h or 15 km in 1h ( PLS HELP ) :(

Mathematics

1 answer:

BigorU [14]2 years ago

6 0

10 km in .5 hour. Since it is the same as 20 km in 1 hour. Multiplied by 2.
20 is greater than 15.
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Irene reads that the 2004 census of whooping cranes tallied 213 birds which is 19 greater than 2003 the growth can be modeled us

lord [1]

Answer: The value of k is 0.09.

Step-by-step explanation:

Since we have given that

$P(t)=P(0)e^{kt}$

Here, k is the rate ,

t is the time,

In 2004, the whooping cranes tallied 213 birds,

So, P(t)=213

It is 19 greater than 2003,

So, P(0)=213-19=194

So, substitute all the values in given expression:

$213=194e^{k.1}\\\\\dfrac{213}{194}=e^k\\\\1.098=e^k\\\\\text{Taking log on both the side}\\\\\ln 1.098=k\\\\k=0.09$

Hence, the value of k is 0.09.

3 0

2 years ago

What is a logarithm? if your employer asked you to select one of these options: option 1: your salary for the next two months wi

Paladinen [302]

Take option 2.
Let n=2^30
Then:
ln n=ln 2^30=30 ln 2
ln n=20.8
n=e^20.8, or 1,073,741,824
1073741824 x.01=$10,737,418.24 due in salary at the end of the first month!!!!!

8 0

2 years ago

if the rate of change of a population is given by dP/dt=3.1(P-2)(P-10), P>0, for what values of P is the population increasin

Gemiola [76]

You have to test dp/dt between these intervals
(-inf,2)
(2,10)
(10,inf)
if dp/dt is positive then the population is increasing with respect to time in that interval

6 0

2 years ago

6. Suppose that a fair coin is tossed 2 times, and the result of each toss (H or T) is recorded.

nekit [7.7K]

Answer:

a) $S= {HH, HT, TH, TT}$

b) $P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25$

$P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5$

$P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25$

And we have the following table:

X | 0 | 1 | 2

P(X) | 0.25 | 0.5 | 0.25

Step-by-step explanation:

Let's define first some notation

H= represent a head for the coin tossed

T= represent tails for the coin tossed

We are going to toss a coin 2 times so then the size of the sample size is $2^2 = 4$

a. What is the sample space for this chance experiment?

The sampling space on this case is given by:

$S= {HH, HT, TH, TT}$

b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.

The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

$P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25$

$P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5$

$P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25$

And we have the following table:

X | 0 | 1 | 2

P(X) | 0.25 | 0.5 | 0.25

5 0

2 years ago

Savannah recorded the average rainfall amount, in inches, for two cities over the course of 6 months.

klasskru [66]

The median for city A is 4 and the median for city B is 5.25.

4 0

3 years ago