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Crank
3 years ago
10

PLEASE ANSWER !! And explain step by step

Mathematics
1 answer:
Ugo [173]3 years ago
5 0

to identify all of the Sims, products and factors in the expression you have to work it out step-by-step so basically we have x + 5, y + 9 + 2 + x parentheses y + 23 and then you multiply and start from there

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What is 0.0000000345 in scientific notation?
spin [16.1K]
Since the number is less that 1, the exponent will be a negative.
3.45X10^-8
5 0
3 years ago
PART A: Maria rented a coat at $285 for 3 days. If she rents the same coat for 60 days, she has to pay a total rent of $510. Wri
Dmitriy789 [7]
<span>1) Name the variables

Number of days: x

rent: y

2) state the initial points

   x           y
days        $

  3           285

60           510


3) assume linear relation:

=> (y - yo) / (x - xo) = (y1 - yo) / (x1 - xo)

=> (y - 285) / (x - 3) = (510 - 285) / (60 - 3)

=> (y - 285) / (x - 3) = 225 / 57 = 75 / 19

=> 19 (y - 285) = 75 (x - 3)

=> 19y - 19*285 = 75x - 75*3

=> 19y - 75x = 5415 - 225

=> 19y  - 75x = 5190

=> standar form = -75x + 19y = 5190


PART B: Write the equation obtained in Part A using function notation.

-75x + 19y = 5190

=> 19y = 5190 + 75x

=> y = 5190/19 + (75/19)x

=> function notation = f(x) = (75/19)x + 5190 / 19

PART C: Describe the steps to graph the equation obtained above on the coordinate axes. Mention the labels on the axes and the intervals.

1) Coordinate axes:

x: number of days

y: rent

2) draw the two given points: (3,285) and (60, 510)

3) draw the line that joins those points from the interception of the y-axis until some points further (60, 510).
</span>
6 0
3 years ago
How do you find the scale of a drawing
Ratling [72]
“Start by measuring the width and height of the object you'll be scaling. Next, choose a ratio to resize your drawing, such as 2 to 1 to double the image in size. Then, multiply your measurements by the first number in your ratio to increase the size.”
5 0
3 years ago
The standard deviation of test scores on a certain achievement test is 11.3. If a randomsample of 81 students had a sample mean
Svetradugi [14.3K]

Answer: (72.535, 76.665)

Step-by-step explanation:

The confidence interval for population mean is given by :-

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where \sigma = population standard deviation.

n= Sample size

\overline{x} = sample mean.

z^* = Critical z-value (two-tailed)

Given : \sigma=11.3

n= 81

\overline{x}=74.6

The critical values for 90% confidence interval : z^*=\pm1.645

Now, the confidence interval for population mean would be :

74.6\pm (1.645)\dfrac{11.3}{\sqrt{81}}\\\\=74.6\pm(1.645)(\dfrac{11.3}{9})\approx74.6\pm2.065\\\\=(74.6-2.065,\ 74.6+2.065)\\\\=(72.535,\ 76.665)

Hence, a 90 percent confidence interval estimatefor the average score of all students. : (72.535, 76.665)

8 0
3 years ago
Evaluate the expression for m=4 n=5 p=-2<br> -n^m
irina1246 [14]
-5^4
= -625

-5 • -5 • -5 • -5 = -625
5 0
3 years ago
Read 2 more answers
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