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Answer:
6,226 tiles of 9 in are needed to cover an area of 400 square feet
Step-by-step explanation:
Let
A -----> an area in square feet
t(A) ---> the total number of 9 in. tiles needed
we have
For A=400 ft^2
substitute in the equation and solve for t
That means -----> 6,226 tiles of 9 in are needed to cover an area of 400 square feet