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Lunna [17]
3 years ago
13

How do you reflect across the x-axis?

Mathematics
1 answer:
Vsevolod [243]3 years ago
7 0
The x-axis is the horizontal line. You can reflect across it by having two points that make a line across it an example is (2,3) and (2,-3)
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George collects 25 baseball cards each month. How many cards will he have at the end of one year? Complete the equation to help
kaheart [24]
25(cards per month) x12(months in one year) =300 cards at the end of one whole year
4 0
3 years ago
Read 2 more answers
Which definite integral approximation formula is this: the integral from a to b of f(x)dx ≈ (b-a)/n * [<img src="https://tex.z-d
Stella [2.4K]

The answer is most likely A.

The integration interval [<em>a</em>, <em>b</em>] is split up into <em>n</em> subintervals of equal length (so each subinterval has width (<em>b</em> - <em>a</em>)/<em>n</em>, same as the coefficient of the sum of <em>y</em> terms) and approximated by the area of <em>n</em> rectangles with base (<em>b</em> - <em>a</em>)/<em>n</em> and height <em>y</em>.

<em>n</em> subintervals require <em>n</em> + 1 points, with

<em>x</em>₀ = <em>a</em>

<em>x</em>₁ = <em>a</em> + (<em>b</em> - <em>a</em>)/<em>n</em>

<em>x</em>₂ = <em>a</em> + 2(<em>b</em> - <em>a</em>)/<em>n</em>

and so on up to the last point <em>x</em> = <em>b</em>. The right endpoints are <em>x</em>₁, <em>x</em>₂, … etc. and the height of each rectangle are the corresponding <em>y </em>'s at these endpoints. Then you get the formula as given in the photo.

• "Average rate of change" isn't really relevant here. The AROC of a function <em>G(x)</em> continuous* over an interval [<em>a</em>, <em>b</em>] is equal to the slope of the secant line through <em>x</em> = <em>a</em> and <em>x</em> = <em>b</em>, i.e. the value of the difference quotient

(<em>G(b)</em> - <em>G(a)</em> ) / (<em>b</em> - <em>a</em>)

If <em>G(x)</em> happens to be the antiderivative of a function <em>g(x)</em>, then this is the same as the average value of <em>g(x)</em> on the same interval,

g_{\rm ave}=\dfrac{G(b)-G(a)}{b-a}=\dfrac1{b-a}\displaystyle\int_a^b g(x)\,\mathrm dx

(* I'm actually not totally sure that continuity is necessary for the AROC to exist; I've asked this question before without getting a particularly satisfying answer.)

• "Trapezoidal rule" doesn't apply here. Split up [<em>a</em>, <em>b</em>] into <em>n</em> subintervals of equal width (<em>b</em> - <em>a</em>)/<em>n</em>. Over the first subinterval, the area of a trapezoid with "bases" <em>y</em>₀ and <em>y</em>₁ and "height" (<em>b</em> - <em>a</em>)/<em>n</em> is

(<em>y</em>₀ + <em>y</em>₁) (<em>b</em> - <em>a</em>)/<em>n</em>

but <em>y</em>₀ is clearly missing in the sum, and also the next term in the sum would be

(<em>y</em>₁ + <em>y</em>₂) (<em>b</em> - <em>a</em>)/<em>n</em>

the sum of these two areas would reduce to

(<em>b</em> - <em>a</em>)/<em>n</em> = (<em>y</em>₀ + <u>2</u> <em>y</em>₁ + <em>y</em>₂)

which would mean all the terms in-between would need to be doubled as well to get

\displaystyle\int_a^b f(x)\,\mathrm dx\approx\frac{b-a}n\left(y_0+2y_1+2y_2+\cdots+2y_{n-1}+y_n\right)

7 0
3 years ago
Y=-2/3x+2, y=3/2x+8 these lines are <br> A) parallel<br> B)perpendicular<br> C)neither
OLga [1]

Answer:

B) perpendicular

Step-by-step explanation:

i graphed them

7 0
3 years ago
Please help!!! I just need a simple explanation I will mark brainliest!
aniked [119]

Answer:

I have made it in above figure so each angle will 150 degree

6 0
3 years ago
Question 1 (1 point) Point M is the midpoint of AB. The coordinates of point A are (-6, 3) and the coordinates of M are (-1, 1).
konstantin123 [22]

Answer:

The answer to your question is:  (4, -1)

Step-by-step explanation:

M = midpoint   (-1, 1)

A = (-6, 3)

B = (x, y)

xm = \frac{x1 + x }{2}

x = 2xm - x1

x = 2(-1) + 6

x = -2 + 6

x = 4

ym = \frac{y1 + y }{2}

y = 2ym - y1

y = 2(1) - 3

y = 2 - 3

y = -1

4 0
3 years ago
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