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3 years ago

(pleas help) Which statement describes the following expression? 6 x (3,117 + 724)

Mathematics

2 answers:

miskamm [114]3 years ago

3 0

Answer:

6 times the value of 3,117 plus 724

Step-by-step explanation:

Hope that helps :)

VikaD [51]3 years ago

3 0

6 times the value of 3,117 plus 724. That’s the correct answer as well (that was repeated by someone)

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PLEASE HELP!!!! :(

AlladinOne [14]

The tangent of the angle gives the ratio of the height of the lighthouse to the boat's distance
.. tan(angle of depression) = (lighthouse height)/(boat distance)
Then the distance to the boat is
.. boat distance = (lighthouse height)/tan(angle of depression)

We want to find the difference between two distances, so
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.. = (200 ft)*(1/tan(17°31') -1/tan(46°41'))
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3 years ago

14. The least common multiple of 2, 5, 6, and 9 is

CaHeK987 [17]

Answer:

Step-by-step explanation:

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3 years ago

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John is 5 years younger than three times his brother’s age. If the sum of their

torisob [31]

Answer:

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Step-by-step explanation:

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1 year ago

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a collector has 80 jackeys and 125 shirts she wants to maintain ratio in her collection but she needs to sell some of her items

Irina18 [472]

Answer:

Step-by-step explanation:

Well, we need to simplify this. we have a ratio of 80:125.

As these numbers end in either 0 or 5, we know they are divisible by 5.

By dividing these by five, our ratio becomes 16:25.

As we have 16 jackets, we know we must need to sell 25 jackets to maintain the ratio.

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3 years ago

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon

fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that $n = 603, \pi = \frac{142}{603} = 0.2355$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

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2 years ago