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zheka24 [161]
3 years ago
9

What is the constant rate of change? A 2 B 4 C 1/2 D -2

Mathematics
2 answers:
timofeeve [1]3 years ago
7 0
It would be c because that would be your slope to get from the first bottom point to the next point which would be (5,-2) and the so on so forth
erica [24]3 years ago
7 0

Answer:

C- 1/2

Step-by-step explanation:

the graph shows a line that goes up 1 square, and to the right 2 squares. Put x over y and you get 1/2, your answer.

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What is the volume of the can below? Use<br> 3.14 and round your answer to the nearest tenth.
Mamont248 [21]

Answer:

328,268.16

Step-by-step explanation:

3.14r^2h

3.14(33)(33)(96)

= 328,268.16

4 0
3 years ago
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93 times 34, I'm multiplying whole numbers.
Papessa [141]
3,162? I think it’s that I’m not sure.
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2 years ago
A circle is divided into 6 equal parts. What is the angle measure of 1 part?
drek231 [11]
The angle measure of one part will be 60.

360/6 = 60 

That is because the circle it divided into 6 equal parts and the whole circle is 360.

Hope this helps :)
7 0
3 years ago
Last week Karen spent $121.35 on food for her family. She only has $200 to spend every two weeks. How much does hse have left to
yan [13]

Answer:

$78.65

Step-by-step explanation:

take 200-121.35=78.65

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5 0
3 years ago
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A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of
jenyasd209 [6]

Answer:

Ix = Iy = \frac{ρπR^{4} }{16}

Radius of gyration x = y =  \frac{R}{4}

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is \frac{MR^{2} }{2}. Moment of inertia of quarter disk about its perpendicular is \frac{MR^{2} }{8}.

Now using perpendicular axis theorem, Ix = Iy = \frac{MR^{2} }{16} = \frac{ρπR^{4} }{16}.

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0
3 years ago
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