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Tema [17]
3 years ago
10

If the value of 2x3 is 2, then what is the value of x?

Mathematics
2 answers:
slavikrds [6]3 years ago
7 0
Hi there!

• 2x³ = 2

Dividing th' eqn. by 2 :-

\dfrac {2}{2} x³ = \dfrac {2}{2}

x³ = 1

x = \sqrt[3]{1}

x = 1

~ Hope it helps!
erastovalidia [21]3 years ago
6 0
Assuming 2x3 = 2x^3,

Divide both sides by 2:

x^3 = 1

Cube root both sides:

\sqrt[3]{1} = 1
x = 1

The value of x is 1.
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Please solve y=x^2-6x-5 by factoring and by using the quadratic formula with work attached
Lynna [10]

<u>Factoring:</u>

This equation cannot be factored because its roots are irrational (as shown by solving with the quadratic formula).  Also, to factor a quadratic equation, you need to find a pair of numbers whose product is equal to the c term (-5) and whose sum is equal to the b term (-6).  There is no pair of numbers which satisfies this, further showing that the equation cannot be factored.


<u>Quadratic Formula:</u>

The quadratic formula is x=\frac{-b ± \sqrt{b^{2}-4ac } }{2a}.

First, you need to find the a, b and c terms of your equation.  They are 1, -6, and -5 respectively.

Now, you must plug in to the equation and solve for x.  You must do so twice, once with a plus sign in the numerator and once with a minus.

\frac{6 ± \sqrt{(-6)^{2}-4(1)(-5) } }{2(1)} \\\frac{6 ± \sqrt{36+20} }{2} \\\frac{6 ± \sqrt{56} }{2} \\\ \frac{6 ± 2\sqrt{14} }{2} \\3+\sqrt{14} \\3-\sqrt{14}


The answers are 3+√14 and 3-√14.


Hope this helps!!


3 0
3 years ago
I need an answer for number 5
notka56 [123]

Answer:

Step-by-step explanation:

Go

7 0
3 years ago
Please help me with this
Kisachek [45]

All you need to do is replace the variables with the numbers given.

t=9 & u=11

3+ 11t - 9u

3+ 11(9)-9(11)

3+ 99 - 99

The 99's cancel each other out, so you are left with 3.

The answer is 3.



7 0
3 years ago
Read 2 more answers
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