The work become much simpler if you do it in a table. Hope this helps!!
Answer:
-2y^2 + y +32
Step-by-step explanation:
The variable with the highest exponent is y^2
Note that if
![{x_2}'=x_1](https://tex.z-dn.net/?f=%7Bx_2%7D%27%3Dx_1)
, then
![{x_2}''={x_1}'](https://tex.z-dn.net/?f=%7Bx_2%7D%27%27%3D%7Bx_1%7D%27)
, and so we can collapse the system of ODEs into a linear ODE:
![{x_2}''=3{x_2}'-x_2+e^t](https://tex.z-dn.net/?f=%7Bx_2%7D%27%27%3D3%7Bx_2%7D%27-x_2%2Be%5Et)
![{x_2}''-3{x_2}'+x_2=e^t](https://tex.z-dn.net/?f=%7Bx_2%7D%27%27-3%7Bx_2%7D%27%2Bx_2%3De%5Et)
which is a pretty standard linear ODE with constant coefficients. We have characteristic equation
![r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0](https://tex.z-dn.net/?f=r%5E2-3r%2B1%3D%5Cleft%28r-%5Cdfrac%7B3%2B%5Csqrt5%7D2%5Cright%29%5Cleft%28r%2B%5Cdfrac%7B3%2B%5Csqrt5%7D2%5Cright%29%3D0)
so that the characteristic solution is
![{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}](https://tex.z-dn.net/?f=%7Bx_2%7D_C%3DC_1e%5E%7B%283%2B%5Csqrt5%29%2F2%5C%2Ct%7D%2BC_2e%5E%7B-%283%2B%5Csqrt5%29%2F2%5C%2Ct%7D)
Now let's suppose the particular solution is
![{x_2}_p=ae^t](https://tex.z-dn.net/?f=%7Bx_2%7D_p%3Dae%5Et)
. Then
![{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t](https://tex.z-dn.net/?f=%7Bx_2%7D_p%3D%7B%7Bx_2%7D_p%7D%27%3D%7B%7Bx_2%7D_p%7D%27%27%3Dae%5Et)
and so
![ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1](https://tex.z-dn.net/?f=ae%5Et-3ae%5Et%2Bae%5Et%3D-ae%5Et%3De%5Et%5Cimplies%20a%3D-1)
Thus the general solution for
![x_2](https://tex.z-dn.net/?f=x_2)
is
![x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t](https://tex.z-dn.net/?f=x_2%3DC_1e%5E%7B%283%2B%5Csqrt5%29%2F2%5C%2Ct%7D%2BC_2e%5E%7B-%283%2B%5Csqrt5%29%2F2%5C%2Ct%7D-e%5Et)
and you can find the solution
![x_1](https://tex.z-dn.net/?f=x_1)
by simply differentiating
![x_2](https://tex.z-dn.net/?f=x_2)
.
Answer:
If the price of a product decreases from $10 to $8, leading to an increase in quantity demanded from 40 to 60 units.
Step-by-step explanation:
Answer:
Group b most likely has a lower mean age of salsa students
Step-by-step explanation:
Arithmetic Mean of the data is the average of a set of numerical values, calculated by adding them together and dividing by the number of terms in the set.
Here we are given with two groups that are Group A and Group B
both having total number of students = 20
Here the mean age of the data is addition of the all ages of different students divided by total number of students.
For group a
total age of the group = 3 × 5 + 4 × 10 + 6 × 17 + 4 × 24 + 3 × 29
= 15 + 40 + 102 + 96 + 87
=340
The mean age of salsa students= 340 ÷ 20 = 17
For group b
total age of the group = 6 × 7 + 3 × 10 + 4 × 14 + 5 × 16 + 2 × 21
= 42 + 30 + 56 + 80 + 42
=250
The mean age of salsa students= 250 ÷ 20 = 12.5
So the group b most likely has a lower mean age of salsa students
Learn more about Arithmetic Mean here - brainly.com/question/24688366
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