Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
Answer:
its C.
Step-by-step explanation:
omg that took forever to solve
Answer:
The possible outcomes are H1, H2, T1, and T2
Step-by-step explanation:
You can result in Heads and one, Heads and two, Tails and one, or Tails and two. Hope this helps!
Answer:
B
Step-by-step explanation:
B is the correct answer.
