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2 years ago

Complete the function for this graph.

Mathematics

1 answer:

Usimov [2.4K]2 years ago

8 0

Answer:

k(x) = -2|x - (-3)| + 4

Step-by-step explanation:

Parent function for the graph is,

f(x) = |x|

If the parent function is vertically stretched by a scale factor of 2,

New function will be,

g(x) = 2|x|

If the function 'g' is reflected across x-axis,

h(x) = -2|x|

If the function 'h' is translated 3 units left and 4 units upwards, new function will be,

k(x) = -2|x - (-3)| + 4

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Answer:

1 quarter, 1 dime, and 4 nickels

Step-by-step explanation:

First you subtract the 18 cents that were found in the pocket from the total amount of 73 cents to get the total amount of the 6 other coins:

73-18=55.

So the total amount of the 6 coins equals 55 cents.

The quarter = 25 cents

The dime = 10 cents

The 4 nickels = 5 + 5 + 5 + 5 = 20

1 quarter, 1 dime, and 4 nickels add up to the necessary total of 6 coins and when you add up the total cents of the quarter, dime, and nickels, 25 + 10 + 20 it comes to the sum of 55, which is how much the 6 coins are worth in total.

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2 years ago

Eighty less than three times a number?

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Answer:

30 x 3 - 80 is 10

Step-by-step explanation:

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2 years ago

Read 2 more answers

Suppose you drive a car 392 miles on one tank of gas. The tank holds 14 gallons of gas. (Assume the car travels the same distanc

RUDIKE [14]

Answer:

Step-by-step explanation:

Suppose you drive a car 392 miles on one tank of gas. The tank holds 14 gallons of gas. This means that

1 gallon of gas would be used to drive 392/14 = 28 miles

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Let x =number of gallons of gas you use.

Let y = the number of miles travelled.

Since y varies directly with x, we will introduce a constant of proportionality, k. Therefore,

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3 years ago

Explain why the function is discontinuous at the given number

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For $f$ to be continuous at $x=5$ , we need to have

$\displaystyle\lim_{x\to5}f(x)=f(5)$

Note that $x\to5$ means that $x\neq5$ , but that $x$ is *approaching* 5. We're told that for $x\neq5$ , we have

$f(x)=\dfrac{x^2-5x}{x^2-25}$

We can write

$\dfrac{x^2-5x}{x^2-25}=\dfrac{x(x-5)}{(x+5)(x-5)}=\dfrac x{x+5}$

and the limit would be

$\displaystyle\lim_{x\to5}\frac x{x+5}=\dfrac5{5+5}=\dfrac5{10}=\dfrac12\neq1=f(5)$

and so $f$ is discontinuous.

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2 years ago

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(176/35)^c=288°

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2 years ago