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Viktor [21]
2 years ago
5

What is the value of x

Mathematics
1 answer:
Gemiola [76]2 years ago
6 0

9514 1404 393

Answer:

  x = 10

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relation ...

  Sin = Opposite/Hypotenuse

  sin(30°) = 5/x

Solving for x, we get ...

  x = 5/sin(30) = 5/0.5

  x = 10

_____

It can be helpful to remember that the side ratios in a 30°-60°-90° triangle are ...

  1 : √3 : 2

That is, the hypotenuse is 2 times the length of the side opposite the 30° angle. Here, that means x = 2×5 = 10, as we found above.

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Solve the matrix equation below
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Answer:

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  • Hence [-4 0: 0 - 2 ] +[0 -3: 5 -4] X + [ 0 -3: 5 -4 ] = [19 -27 : 10 -24]
6 0
3 years ago
Carla's Plumbing charges $25 for a service call and $28 per hour, h, for labor for any repair. The total cost, t, for a repair c
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

4 0
2 years ago
The median weight for a 5 foot tall male to enlist in the US Army is 114.5 lbs. This weight can vary by 17.5 lbs. Write and solv
myrzilka [38]

An absolute value inequality that represents the weight of a 5-foot male who would not meet the minimum or maximum weight requirement allowed to enlist in the Army is 97 lbs < x < 132 lbs.

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.

It is mostly denoted by the symbol <, >, ≤, and ≥.

The median weight for a 5 foot tall male to enlist in the US Army is 114.5 lbs. This weight can vary by 17.5 lbs. Therefore, the inequality can be written as,

(114.5 - 17.5) lbs < x < (114.5 + 17.5) lbs

97 lbs < x < 132 lbs

Hence, an absolute value inequality that represents the weight of a 5-foot male who would not meet the minimum or maximum weight requirement allowed to enlist in the Army is 97 lbs < x < 132 lbs.

Learn more about Inequality:

brainly.com/question/19491153

#SPJ1

4 0
2 years ago
The sea turtle habitat at the zoo is made by connecting two large aquariums. The first aquarium is 6\text { m}6 m6, space, m lon
iren [92.7K]

First aquarium dimensions:

Length = 6 m.

Width = 4 m and

Height = 2 meter.

Second aquarium dimensions:

Length = 8 m.

Width = 9 m and

Height = 3 meter.

We know formula for volume of a cuboidal box = Length*Width*Height.

Plugging values of length, width and height of first aquarium in formula of volume. We get

V1 = 6*4*2 = 48 m^3.

Plugging values of length, width and height of second aquarium in formula of volume. We get

V2 = 8*9*3 = 216 m^3.

In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.

Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.

Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.

8 0
3 years ago
What is this answer?
zhannawk [14.2K]

I'm NOT 100% confident in my answers.

Graph 1:

Range: Option B

Graph 2:

Range: Option A

The range has to start at zero since that's the lowest point we can go, only one with zero is first option.

RATE AS BRAINLIEST

8 0
3 years ago
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