The area of the figure is 104.52 sq inches
<h3>How to determine the area of the figure?</h3>
In the complete figure, we have:
1 Rectangle: Base = 8 in and Height = 6 in
2 semicircles: Diameter = 6 inches
The area of the figure is
Area = Area of rectangle + Sum of Areas of semicircles
This gives
Area = Base * Height + 2 * π(d/2)^2
This gives
Area = 8 * 6+ 2 * 3.14 * (6/2)^2
Evaluate
Area = 104.52
Hence, the area of the figure is 104.52 sq inches
Read more about areas at:
brainly.com/question/24487155
#SPJ1
Answer:
h(4) = 0
Step-by-step explanation:
Hoping its ' kx '
Now we have k = -2. We will find h(4).
A vertical stretch of scale factor 2, followed by a translation of 4 units left and 1 unit down is written as:
g(x) = 2*f(x + 4) - 1
<h3>
How to write the given transformation?</h3>
For a general function f(x), a vertical stretch of scale factor K is written as:
g(x) = K*f(x).
<u><em>Horizontal translation:</em></u>
For a general function f(x), a horizontal translation of N units is written as:
g(x) = f(x + N).
- If N is positive, the shift is to the left.
- If N is negative, the shift is to the right.
<u><em>Vertical translation:</em></u>
For a general function f(x), a vertical translation of N units is written as:
g(x) = f(x) + N.
- If N is positive, the shift is upwards.
- If N is negative, the shift is downwards.
So, if we start with a function f(x) and we stretch it vertically with a scale factor of 2, we get:
g(x) = 2*f(x)
Then we translate it 4 units left:
g(x) = 2*f(x + 4)
Then we translate 1 unit down:
g(x) = 2*f(x + 4) - 1
This is the equation for the transformation.
If you want to learn more about transformations, you can read:
brainly.com/question/4289712
12. 37, 370, 10^2
13. 20.4, 10^2, 2040
15. 1000*1.75=1750
Hope it helped!
The centre of the rotation is A
The line of the reflection is Y
Vertex A of the triangle ABC when rotated by 90° counterclockwise about the origin,
Rule to be followed,
A(x, y) → P(-y, x)
Therefore, A(1, 1) → P(-1, 1)
Similarly, B(3, 2) → Q(-2, 3)
C(2, 5) → R(-5, 2)
Triangle given in second quadrant will be the triangle PQR.
If the point P of triangle PQR is reflected across a line y = x,
Rule to be followed,
P(x, y) → X(y, x)
P(-1, 1) → X(1, -1)
Similarly, Q(-2, 3) → Y(3, -2)
R(-5, 2) → Z(2, -5)
Therefore, triangle given in the fourth quadrant is triangle XYZ.
Learn more about reflection
brainly.com/question/13805069
#SPJ9
