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3 years ago

Need help plzz 20 points

Mathematics

2 answers:

photoshop1234 [79]3 years ago

6 0

Answer:

42 cm

Step-by-step explanation:

Area of rectangle (shaded area):

length × breadth

length: 7 cm

breadth: 7 - 2(0.5) = 6 cm

7 × 6 = 42 cm

Firlakuza [10]3 years ago

3 0

Answer:

42 cm is the correct answer of this one

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Christine has a rectangular poster. The poster is 1.5 meters long and 1.2 meters wide. What is the area of the poster in square

Setler79 [48]

Answer: 180cm^2

Explanation: First, multiply 1.5 by 1.2 to get the area of the rectangle in METERS, which is 1.8. Since the question is asking for the area in CENTIMETERS, multiply 1.8 by 100 (because 1 meter=100 centimeters) to get 180cm^2.

Hope that helped :)

7 0

3 years ago

A rectangular deck has an area of 320ft^2. the length of the deck is 4 feet longer than the width. find the dimensions of the de

Digiron [165]

A = L * W
A = 320
L = W + 4

320 = W(W + 4)
320 = W^2 + 4W
W^2 + 4W = 320
W^2 + 4W + 4 = 320 + 4
(W + 2)^2 = 324
W + 2 = (+-) sqrt 324
W = -2 (+-) 18

W = -2 + 18 = 16 ft <== this is the width
W = -2 - 18 = -20....not this one because it is negative

L = W + 4
L = 16 + 4
L = 20 ft <=== this is the length

in summary...the width is 16 ft and the length is 20 ft

7 0

3 years ago

What decimal is equivalent to 13/10

LUCKY_DIMON [66]

Answer:

1.30

Step-by-step explanation:

because it's 13 / 10 it means that there is a whole number , 13 - 10 equals 3 oh, so you divide 3 from 100

4 0

3 years ago

What are the domain and range of the inequality y < sqrt x+3+1

love history [14]

Given:

The inequality is:

$y$

To find:

The domain and range of the given inequality.

Solution:

We have,

$y$

The related equation is:

$y=\sqrt{x+3}+1$

This equation is defined if:

$x+3\geq 0$

$x\geq -3$

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

$\sqrt{x+3}\geq 0$