Answer:
1
Step-by-step explanation:
(3/5) ^0 ^-2
We know that a^b^c = a^(b*c)
(3/5) ^(0*-2) = (3/5)^0
We know a^0 = 1 as long as a does not equal1
(3/5)^0 =1
Let the width = X
The length would be X + 20
Area = Length x width:
2400 = x * (x+20)
Simplify:
2400 = x^2 + 20x
Subtract 2400 from both sides:
x^2 + 20x - 2400 = 0
Factor:
(x-40) (x+60) = 0
Solve for both x's:
x = 40 and x = -60
The dimensions of a parking lot have to be positive values so you would use x = 40.
The width = x = 40
The length = x +20 = 40+20 = 60
The dimension of the parking lot is 40H x 60H
F(X) = 4x - 5
G(X) = 6x - 3
F(x) - G(x)
(4x - 5) - (6x - 3)
4x - 5 - 6x + 3
-2x - 2
-2(X + 1).
I believe this would be the simplified solution.
Answer:
The answer is 80 degrees, I believe
