Answer:
1000 cm²
Step-by-step explanation:
Given:
- Length = 10 cm
- Width = 12.5 cm
- Height = 8 cm
<u>Formula:</u>

Substitute the length, width, and the height of the prism to determine the volume of the prism.

Simplify the right hand side of the equation, as needed;



Therefore, the volume of the prism is 1000 cm².
Hi
312 bolts ⇒ 30 min
260 bolts ⇒ x min
312x = 30·(260)
312x = 7800
x = 7800/312
x = 25 min
Answer: 25 minutes
Step-by-step explanation:
Left hand side:
tan 203° + tan 22° + tan 203° · tan 22°
From angle sum identities, we know:
tan (α + β) = (tan α + tan β) / (1 − tan α · tan β)
Therefore:
tan (203° + 22°) = (tan 203° + tan 22°) / (1 − tan 203° · tan 22°)
tan (225°) = (tan 203° + tan 22°) / (1 − tan 203° · tan 22°)
1 = (tan 203° + tan 22°) / (1 − tan 203° · tan 22°)
tan 203° + tan 22° = 1 − tan 203° · tan 22°
Substituting:
1 − tan 203° · tan 22° + tan 203° · tan 22°
1
Answer:
The measures of angles of triangle MNP are
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
step 1
Find the measure of arcs AB, BC and AC
we know that
The inscribed angle is half that of the arc it comprises.
so
step 2
Find the measure of angle M
we know that
The measurement of the outer angle is the semi-difference of the arcs it encompasses.
![M=\frac{1}{2}[arc\ AB+arc\ BC-arc\ AC]](https://tex.z-dn.net/?f=M%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20AB%2Barc%5C%20BC-arc%5C%20AC%5D)
substitute
![M=\frac{1}{2}[2\gamma+2\alpha-2\beta]\\M=[\gamma+\alpha-\beta]](https://tex.z-dn.net/?f=M%3D%5Cfrac%7B1%7D%7B2%7D%5B2%5Cgamma%2B2%5Calpha-2%5Cbeta%5D%5C%5CM%3D%5B%5Cgamma%2B%5Calpha-%5Cbeta%5D)
step 3
Find the measure of angle N
we know that
The measurement of the outer angle is the semi-difference of the arcs it encompasses.
![N=\frac{1}{2}[arc\ AC+arc\ BC-arc\ AB]](https://tex.z-dn.net/?f=N%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20AC%2Barc%5C%20BC-arc%5C%20AB%5D)
substitute
![N=\frac{1}{2}[2\beta+2\alpha-2\gamma]\\N=[\beta+\alpha-\gamma]](https://tex.z-dn.net/?f=N%3D%5Cfrac%7B1%7D%7B2%7D%5B2%5Cbeta%2B2%5Calpha-2%5Cgamma%5D%5C%5CN%3D%5B%5Cbeta%2B%5Calpha-%5Cgamma%5D)
step 4
Find the measure of angle P
we know that
The measurement of the outer angle is the semi-difference of the arcs it encompasses.
![P=\frac{1}{2}[arc\ AC+arc\ AB-arc\ BC]](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20AC%2Barc%5C%20AB-arc%5C%20BC%5D)
substitute
![P=\frac{1}{2}[2\beta+2\gamma-2\alpha]\\P=[\beta+\gamma-\alpha]](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7B2%7D%5B2%5Cbeta%2B2%5Cgamma-2%5Calpha%5D%5C%5CP%3D%5B%5Cbeta%2B%5Cgamma-%5Calpha%5D)