4b^2 - 16 =
4(b^2 - 4) =
4(b + 2)(b - 2)
Answer:
Below.
Step-by-step explanation:
- tan 2x = -2tanx / (1 - tan^2x)
Using the identity tan^2x = sec^2x - 1 and substituting for tan^2x:
- tan 2x = -2 tanx / (1 - (sec^2x - 1))
= 2 tanx / ( - 1(sec^2x + 2))
= 2 tan x / (sec^2 x - 2)
Answer:
Graph of Modulus
The graph of a modulus or absolute value function is in a form of a 'V' shape whose vertex depends upon the coordinates. The equation for the graph is given as,
where,
(a, b) are the coordinates of the vertex of 'v' in the form of (x, y),
And h shows how wider or lean will be the function, for h=0, it is a straight line, while for a negative value the graph will face downwards and opposite for a positive value.
Given to us
y = |x-3|
On the coordinate plane
The graph will be in the shape of a 'V' whose vertex will lay at the coordinates (3, 0). As the value of a is 1 the graph will face upwards. As shown below on the graph.
Learn more about Modulus:
brainly.com/question/18106342
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
