Answer:
the other variable is also doubled
Explanation:
direct proportion, same thing has to happen to both variables
The peptide given above is made up of the following amino acids: glycine [G], leucine [L], valine [V], isoleucine [I] and tryptophan [W]. These amino acids are joined together by amide bond to form peptide. Peptides usually have two terminals, the N terminal and the C terminal. For GLVIW, the C terminal end amino acid is tryptophan, that is the last amino acid on the peptide chain. The N terminal amino acid is glycine, that is, the first amino acid on the peptide chain.
Answer:
The value is 
Explanation:
From the question we are told that
The molar mass of
is 
The total mass is
The uncertainty of the total mass is 
Generally the molar weight of calcium is 
The percentage of calcium in calcite is mathematically represented as


Generally the mass of each sample is mathematically represented as



Generally mass of calcium present in a single sample is mathematically represented as


The uncertainty of mass of a single sample is mathematically represented as



The uncertainty of mass of calcium in a single sample is mathematically represent

Generally the average mass of calcium in each sample is

Answer:
Molarity = 0.5 M
Explanation:
Given data:
Mass of NaCl = 2.7 g
Volume = 100 mL(100×10⁻³L)
Molarity of solution = ?
Solution:
Formula:
Molarity = number of moles / volume in litter
Number of moles:
Number of moles = mass/ molar mass
Number of moles = 2.7 g/ 58.5 g/mol
Number of moles = 0.05 mol
Molarity = number of moles / volume in litte
Molarity = 0.05 mol / 100×10⁻³L
Molarity = 0.5 M