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harkovskaia [24]
3 years ago
7

Joe earned 2,100$.He spent 1/5 on rent and 1/3 on food.How much money did he have left​

Mathematics
2 answers:
ra1l [238]3 years ago
6 0

Answer:

$980

Step-by-step explanation:

Step 1: Find \frac{1}{5} of 2100 = 420

  • \frac{1}{5}\times \:2100
  • Convert 2100 to a fraction: \:2100=\frac{2100}{1}
  • =\frac{1}{5}\times \frac{2100}{1}
  • Cross Divide
  • 2100 \div 5 = 420

Step 2: Find \frac{1}{3} of 2100 = 700

  • \frac{1}{3}\times \:2100
  • Convert 2100 to a fraction: \:2100=\frac{2100}{1}
  • =\frac{1}{3}\times \frac{2100}{1}
  • Cross Divide
  • 2100 \div 3 = 700

Step 3: Add both results together

420 + 700 = 1120

Step 4: Subtract the result from how much joe earns ($2,100)

2100 - 1120 = 980

Joe has $980 left

gavmur [86]3 years ago
3 0

Answer:

$980

Step-by-step explanation:

1/5 of 2100 is 420, and 1/3 of 2100 is 700, so he spent $1120 in total. Subtract that from 2100, and you get $980 as your answer. Hope this helps!

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Answer:

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Step-by-step explanation:

Given:

The shape of the tank is obtained by revolving y=x^2 about y axis in the interval 0\leq x\leq 3.

Density of the fluid in the tank, D=100\ lbs/ft^3

Let the initial height of the fluid be 'y' feet from the bottom.

The bottom of the tank is, y(0)=0^2=0

Now, the height has to be raised to a height 5 feet above the top of the tank.

The height of top of the tank is obtained by plugging in x=3 in the parabolic equation . This gives,

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Now, 5 ft above 'H' means H+5=9+5=14

Therefore, the increase in height of the top surface of the fluid in the tank is given as:

\Delta y=(14-y) ft

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A(y)=\pi r^2\\r\to radius\ of\ the\ cross\ section

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W=100\int\limits^9_0 {\pi (\sqrt y)^2(14-y)} \, dy\\\\W=100\pi\int\limits^9_0 { (\sqrt y)^2(14-y)} \, dy\textrm{ ft-lbs}

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