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3 years ago

Solve the equation for all real solutions in simplest form. -3w^2-10w+1=\,\,-4w^2−4w 2

Mathematics

1 answer:

Ierofanga [76]3 years ago

3 0

Here is the answer. Let me know if you need any clarification!

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Find the length of the following two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16

andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$

Doing the operations inside of the brackets the derivatives are:

1 ) $(\frac{d((1/2)t^2)}{dt} )^2= t^2$

2) $\frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1$

Entering these values of the integral is

$r(t)= \int\limits^{16}_{0} \sqrt{t^2 +2t+1} dt$

It is possible to factorize the quadratic function and the integral can reduced as,

$r(t)= \int\limits^{16}_{0} (t+1) dt= \frac{t^2}{2} + t$

Thus, evaluate from 0 to 16

$\frac{16^2}{2} + 16$

The value is $r= 144 units$

5 0

3 years ago

Please help! It’s urgent!

Gre4nikov [31]

Answer:

9/35

all the boxes in one row are 7 and the number of rows are 5 .. so 7x5=35 and the number of boxes shaded are 9

5 0

2 years ago

In the isosceles triangle ABC, we have AB=AC=4. The altitude from B meets AC at H. If AH=3(HC) then determine BC.

Inga [223]

Answer:

BC=√7

Step-by-step explanation:

AC=4

AC=AH+HC

=3HC+HC

=4HC

HC=1/4AC=1/4×4=1

AH=3HC=3×1=3

BH⊥ AC

AB=AC=4

$BC=\sqrt{AB^2-AH^2} =\sqrt{4^2-3^2} =\sqrt{16-9} =\sqrt{7}$

5 0

3 years ago

John has gross biweekly earnings of $743.61. By claiming 1 more withholding allowance, John would have $19 more in his take home

Afina-wow [57]

Answer:

Total withholding allowances are 39.

Step-by-step explanation:

Given the gross earning of John = $743.61

It is given that 1 withholding allowance = $19

Now we have to find the total number of withholding allowances. Here, the number of withholding allowances can be determined by dividing the total earnings with $19.

Number of withholding allowances = 743.61 / 19 = 39.14 or 39 (round off).

4 0

3 years ago

A survey of 25 grocery stores revealed that the mean price of a gallon of milk was $2.98, with a standard error of $0.10. What i

Gnesinka [82]

Answer:

95% confidence interval: (2.784,3.176)

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 25

Sample mean = $2.98

Standard error = $0.10

Alpha = 0.05

95% confidence interval:

$\mu \pm z_{critical}(\text{Standard error})$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$2.98 \pm 1.96(0.10) = 2.98 \pm 0.196 = (2.784,3.176)$

5 0

3 years ago