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guajiro [1.7K]
3 years ago
8

NEED HELLPPP ASAP (Thank you)

Mathematics
1 answer:
expeople1 [14]3 years ago
4 0

Answer:

ask your teacher it would be good for you and also teachers give u good thing about that okay but i can't help you sorry.

Step-by-step explanation:

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Addition (must show work) can someone solve 1. m + 13 =29 2. z + x =34 <br><br> 3. 87 + p = 136
azamat

Greetings ! Your Answer Is Below.

Answer;

1. m = 16

2. x = -z + 34 or z = -x + 34

3. p = 49

Step-by-step explanation;

1. m + 13 - 13 = 29 - 13       | Subtract 13 from both sides ( m = 16 )

2. - z + 34                          | Add -z to both of the sides ( x = - z + 34 )

Or - x + 34                         | Add -x to both of the sides ( z = - x + 34 )

3. 136 - 87 = 49                 | Subtract 87 from both sides ( p = 49 )

[ Hope This Helped ! ]

3 0
2 years ago
Use the method of Gauss to find the sum.1+2+3+.....+400
nikklg [1K]
Gauss' method for addition relies on the fact that you can 'pair' certain numbers together. Look at the example:

1+2+3+4+5+6+7+8+9+10

We could manually add all these together from left to right but a clever way to think about this is if we add together the ends of the sum (10+1) we get 11. If we then move one in from the ends and add these (2+9) we also get 11. This means that 1+2+...+9+10 is the same as 11+11+...+11+11.

Because each 2 numbers adds to 11 we know the total number of 11's we have to add together is the length of the sum divided by 2. In our case 5 (10 ÷ 2). We need to add 5 lots of 11 to get our answer. This is the same as 11 × 5 which is easily seen to be 55.

(If you add the 10 numbers together on a calculator you'll see 1+2+3+4+5+6+7+8+9+10 = 55) so this method really makes it a lot quicker.

Looking at your sequence, if we pair the ends together we get 401 (400+1) and we multiply this by the length of the sequence divided by 2. In your case, 200 (400 ÷ 2).

So the sum of all the numbers from 1 to 400 must be 401 × 200 = 80,200.

Remember the steps:
1. Pair the ends together and add them
2. Times this number by the length of the sequence halved

Hope this helps.
6 0
3 years ago
Can someone please help me with #3?
kap26 [50]

Answer:


Step-by-step explanation:

First, make sure you know which section of the number line you want as 1 and 2. Next, put 0.25 not right at 0 but very close, then put 0.75 farther but not too much from 0.25. Then for the decimal 1.99 put that very close to where you marked the 2 but, not on the 2. Finally, put 2.03  very close to 2 but not exactly on the 2. Also, make sure that the number line is marked evenly.

7 0
3 years ago
Write each equation in standard form. identify A,B,C.
aleksley [76]
Write in y=ax²+bx+c form
solve for y

given
\frac{x+5}{3}=-2y+4
solve for y

easy
minus 4 both sides
\frac{x+5}{3}-4=-2y
times -1/2 to both sides
\frac{x+5}{-6}+2=y
y=\frac{x+5}{-6}+2
y=\frac{-x}{6}-\frac{6}{5}+2
2=10/5
y=\frac{-1}{6}x-\frac{6}{5}+\frac{10}{5}
y=\frac{-1}{6}x+\frac{4}{5}
y=ax²+bx+c
y=0x^2+\frac{-1}{6}x+\frac{4}{5}

a=0
b=\frac{-1}{6}
c=\frac{4}{5}
3 0
3 years ago
Solve x
d1i1m1o1n [39]

Step-by-step explanation:

x^{2} - 4x - 7 = 0

First, let's move the 7 to the right-hand side so we can determine what constant we'll need on the left-hand side to complete the square:

x^{2} - 4x = 7

From here, since the coefficient of the x term is -4, we know the square will be (x - 2) (since -2 it's half of -4).

To complete this square, we will need to add (-2)^{2} to both sides of the equation:

x^{2} - 4x + (-2)^2 = 7 + ^{-2}

x^{2} - 4x + 4 = 7 + 4

(x - 2)^{2} = 11

Now we can take the square root of both sides to figure out the solutions to x:

x - 2 = \pm \sqrt{11}

x = 2 \pm \sqrt{11}

7 0
3 years ago
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