1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LUCKY_DIMON [66]
2 years ago
8

A box is supposed to have 150 folders in it. Clare counts only 147 folders in

Mathematics
1 answer:
VikaD [51]2 years ago
5 0

Answer:

it's a 0.02% error.

147/150= 0.98% of the folders are there, making the error 0.02%

Step-by-step explanation:

You might be interested in
10x+17+5y+3 what is the answer to my question
Marat540 [252]
You combine everything you can, which is only 17 and 3. So your answer is 10x + 5y + 20
3 0
3 years ago
Read 2 more answers
Bob has a standard deck of playing cards. If he randomly draws a J, K, 2, and 2, what is the probability that the next card he d
nlexa [21]

Answer:

The correct answer has already been given (twice). I'd like to present two solutions that expand on (and explain more completely) the reasoning of the ones already given.


One is using the hypergeometric distribution, which is meant exactly for the type of problem you describe (sampling without replacement):


P(X=k)=(Kk)(N−Kn−k)(Nn)


where N is the total number of cards in the deck, K is the total number of ace cards in the deck, k is the number of ace cards you intend to select, and n is the number of cards overall that you intend to select.


P(X=2)=(42)(480)(522)


P(X=2)=61326=1221


In essence, this would give you the number of possible combinations of drawing two of the four ace cards in the deck (6, already enumerated by Ravish) over the number of possible combinations of drawing any two cards out of the 52 in the deck (1326). This is the way Ravish chose to solve the problem.


Another way is using simple probabilities and combinations:


P(X=2)=(4C1∗152)∗(3C1∗151)


P(X=2)=452∗351=1221


The chance of picking an ace for the first time (same as the chance of picking any card for the first time) is 1/52, multiplied by the number of ways you can pick one of the four aces in the deck, 4C1. This probability is multiplied by the probability of picking a card for the second time (1/51) times the number of ways to get one of the three remaining aces (3C1). This is the way Larry chose to solve the this.

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
If the price of an object dropped 35% down to 91.00, what was the original price?
densk [106]
260 was its original prize.
8 0
3 years ago
Assume that y varies directly with x. If y=2/5 when x=1/3, find y when x=1/4. Enter in any fractions using a / (e.g. "1/2" is th
Oxana [17]

x=3/15 thus y=6/15 If x=1/4 then y =2/4

7 0
2 years ago
Convert. If necessary, round to the nearest tenth.<br> 1.5 oz ≈ ___g
s344n2d4d5 [400]

42.52 g

im pretty sure this is the answer

4 0
3 years ago
Other questions:
  • A board game is played as follows: a number cube numbered 1 to 6 is rolled. If the number 1 comes up, you get nothing. If the nu
    15·1 answer
  • In two or more complete sentences explain the similarities and differences between saving money and investing money.
    15·2 answers
  • What is 14,000,000 in scientific notation?
    10·1 answer
  • Write the equation represents the situation?
    12·1 answer
  • PLEASE HELP EXTRA POINTS / WRONG ANSWERS WILL BE REPORTED
    14·1 answer
  • Find the surface area.<br> 11 in<br> 9 in
    12·1 answer
  • What is g(3) please help
    9·1 answer
  • Helppppppppppp plzzzz
    9·2 answers
  • An engine is operating at 25% of its full power. Which number line shows a point that represents 25%?
    7·1 answer
  • Write a linear function in factored form to represent this scenario. Use f(x) and do not include any spaces in your equation.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!