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Kitty [74]
3 years ago
5

The sequence an = 27( one third )n − 1is graphed below:

Mathematics
2 answers:
ASHA 777 [7]3 years ago
8 0

Answer:

-4

Step-by-step explanation:

THE ANSWER IS -4

PLEASE MARK ME AS BRAINLIEST

Anettt [7]3 years ago
4 0

Answer:

Its -4

Step-by-step explanation:

I took the test and got it right.

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3 0
3 years ago
#1. Which is equal to z3 8? A. (z - 2)(z^2 - 2z - 4). B. (z + 2)(z^2 - 2z + 4) C.(z - 2)(z^2+ 2z + 4). D. (z + 2)(z^2+ 2z - 4) #
tankabanditka [31]
#1. B
<span>(z * z^2 + z * 2z + z * 4) – (-2 *z^2 – (-2) 2z – (-2) 4)
Z^3 + 2z^2 + 4z – 2z^2 -4z – 8
Z^3 + 2z^2 – 2z^2 + 4z – 4z – 8
Z^3 - 8
</span>
#2 and #3. D
<span>(x + y)(x + 2)
x^2 + 2x + yx + 2y
</span>
#4. D.
<span>(x - 7)(x + 7)(x- 2)
x^2 + 7x – 7x -49
x^2 + x – 49
x^2 -49
(x^2 – 49 ) (x – 2)
x^3 – 2x^2 – 49x + 98
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#5. C
(y - 4) = 0
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#6. A and B
3 0
4 years ago
The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by: P(x)=-12x^2 +12
Minchanka [31]

Given:

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

P(x)=-12x^2+120x

To find:

The current that will produce the maximum power.

Solution:

We have,

P(x)=-12x^2+120x

Here, leading coefficient is negative. So, it is a downward parabola.

Vertex of a downward parabola is the point of maxima.

If a parabola is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

In the given function, a=-12 and b=120. So,

-\dfrac{b}{2a}=-\dfrac{120}{2(-12)}

-\dfrac{b}{2a}=-\dfrac{120}{-24}

-\dfrac{b}{2a}=5

Putting x=5 in the given function, we get

P(5)=-12(5)^2+120(5)

P(5)=-12(25)+600

P(5)=-300+600

P(5)=300

Therefore, 5 watt current will produce the maximum power of 300 amperes.

6 0
3 years ago
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