We have the following expression:
(2x ^ 3-12x ^ 2 + 10x-108) / x-6
Dividing the expression between x-6 we have:
quotient: 2x ^ 2 + 10
remainder: - 48
We can check the result then rewriting the expression:
2x ^ 3-12x ^ 2 + 10x-108
= (2x ^ 2 + 10) * (x-6) - 48
= (2x ^ 3 + 10x - 12 x ^ 2 - 60) - 48
= 2x ^ 3-12x ^ 2 + 10x-108
Division OK.
Answer:
The result of the division is:
quotient: 2x ^ 2 + 10
remainder: - 48
Answer:
1)Solving the expression
we get ![\mathbf{x=-\frac{1}{3}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%3D-%5Cfrac%7B1%7D%7B3%7D%7D)
2) solving the equation
we get ![\mathbf{x=2}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%3D2%7D)
Step-by-step explanation:
We need to solve the expressions:
1) ![1-2(2x+1)=1-(x-1)\\](https://tex.z-dn.net/?f=1-2%282x%2B1%29%3D1-%28x-1%29%5C%5C)
Solving
![1-2(2x+1)=1-(x-1)](https://tex.z-dn.net/?f=1-2%282x%2B1%29%3D1-%28x-1%29)
First solving the brackets
![1-4x-2=1-x+1](https://tex.z-dn.net/?f=1-4x-2%3D1-x%2B1)
Simplifying
![-1-4x=-x](https://tex.z-dn.net/?f=-1-4x%3D-x)
Adding 4x on both sides
![-1-4x+4x=-x+4x\\-1=3x](https://tex.z-dn.net/?f=-1-4x%2B4x%3D-x%2B4x%5C%5C-1%3D3x)
Switching the sides
![3x=-1](https://tex.z-dn.net/?f=3x%3D-1)
Divide both sides by 3
![\frac{3x}{3}=-\frac{1}{3}\\x= -\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%7D%7B3%7D%3D-%5Cfrac%7B1%7D%7B3%7D%5C%5Cx%3D%20%20-%5Cfrac%7B1%7D%7B3%7D)
So, Solving the expression
we get ![\mathbf{x=-\frac{1}{3}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%3D-%5Cfrac%7B1%7D%7B3%7D%7D)
2) ![3.6x-6.1=5.9-2.4x](https://tex.z-dn.net/?f=3.6x-6.1%3D5.9-2.4x)
Solving:
![3.6x-6.1=5.9-2.4x](https://tex.z-dn.net/?f=3.6x-6.1%3D5.9-2.4x)
Adding 6.1 on both sides
![3.6x-6.1+6.1=5.9-2.4x+6.1\\3.6x=12-2.4x](https://tex.z-dn.net/?f=3.6x-6.1%2B6.1%3D5.9-2.4x%2B6.1%5C%5C3.6x%3D12-2.4x)
Adding 2.4x on both sides
![3.6x+2.4x=12-2.4x+2.4x\\6x=12\\](https://tex.z-dn.net/?f=3.6x%2B2.4x%3D12-2.4x%2B2.4x%5C%5C6x%3D12%5C%5C)
Divide both sides by 6
![\frac{6x}{6}=\frac{12}{6}\\x=2](https://tex.z-dn.net/?f=%5Cfrac%7B6x%7D%7B6%7D%3D%5Cfrac%7B12%7D%7B6%7D%5C%5Cx%3D2)
So, solving the equation
we get ![\mathbf{x=2}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%3D2%7D)
12(6) + 30(3)
= 72 + 90
= 162
Answer:3200 tickets were ordered in all
Step-by-step explanation:
32x100=3200 since each roll has 100 tickets and there are 32 rolls.
Answer:
The GCF is 25
Step-by-step explanation:
<u>Step 1: Find the factors of both of the numbers</u>
175 -> 1, 5, 7, 25, 35, 175
25 -> 1, 5, 25
<u>Step 2: Find the GCF</u>
The GCF is the number that belongs in both of the sets, 175 and 25. The GCF is the number that is both in 175 and 25 and the highest one of the GCF's. So... for this instance the GCF is 25. By the way I have the GCF bolded on top.
Answer: The GCF is 25