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3 years ago

K(-1)=? need hlep not ask for mush answers quick pls ❤️❤️

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

6 0

The anwser is 7 I’m pretty sure

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2x - 5 = 3x + 4<br> solve for x

Simora [160]

Answer: x = -9. Hope this helps, good luck! :)

6 0

3 years ago

Read 2 more answers

What is the answer to 7b-7-8b= -15

ozzi

Answer:

b=8

Step-by-step explanation:

7b-7-8b=-15

Combine like terms

-b-7=-15

Add 7 on both sides

-b=-15+7

-b=-8

Divide by -1

b = 8

8 0

3 years ago

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Find the following measure for this figure.

miv72 [106K]

l=11
r=5

Now

LSA:-

πrl
π(11)(5)
55πunits ²

4 0

2 years ago

In 2016, the mean score on the AP Art History exam was 3.8, with a standard deviation of 1.2. The mean score on the AP English e

Ulleksa [173]

Answer:

$X+Y \sim N(\mu_X +\mu_Y , \sqrt{\sigma^2_X +\sigma^2_Y})$

The mean is given by:

$\mu = 3.8+2.9= 6.7$

And the standard deviation would be:

$\sigma =\sqrt{1.2^2 + 1.7^2} = 2.08$

And the distribution for X+Y would be:

$X+Y \sim N(6.7 , 2.08)$

And the best answer would be:

D.) Mean, 6.7; standard deviation, 2.08

Step-by-step explanation:

Let X the random variable who represent the AP Art History exam we know that the distribution for X is given by:

$X \sim N(3.8, 1.2)$

Let Y the random variable who represent the AP English exam we know that the distribution for X is given by:

$X \sim N(2.9, 1.7)$

We want to find the distribution for X+Y. Assuming independence between the two distributions we have:

$X+Y \sim N(\mu_X +\mu_Y , \sqrt{\sigma^2_X +\sigma^2_Y})$

The mean is given by:

$\mu = 3.8+2.9= 6.7$

And the standard deviation would be:

$\sigma =\sqrt{1.2^2 + 1.7^2} = 2.08$

And the distribution for X+Y would be:

$X+Y \sim N(6.7 , 2.08)$

And the best answer would be:

D.) Mean, 6.7; standard deviation, 2.08

8 0

3 years ago

Read 2 more answers

PLEASE HELP ME!!

Dimas [21]

A) 8^2 + 12^2=c^2
c= 4(13) or 14.42
B) 8^2 + b^2=12^2
b=4(5) or 8.94

7 0

3 years ago