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Rom4ik [11]
2 years ago
7

PHOTO ATTACHED PLEASEEEE HELPPPP!!!!!!!!!!

Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
6 0

Answer:

15x^2-3x-1

Step-by-step explanation:

All we have to do is collect like terms and calculate! Hope this helps!

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What is the value of 36X negative Y over to when X equals three and Y equals -6
Rus_ich [418]

<u><em>Note:</em></u>

<em>Your question is a little unclear. But, from my understanding, I assume you may be asking the evaluation of the expression 36x - y when x = 3 and y = -6.</em>

<em>so I will solve based on my assumption which anyways would clear your concept.</em>

Answer:

The value of 36x - y when x = 3 and y = -6 will be: 114

Step-by-step explanation:

Given

Assuming the expression

36x - y

To Determine

Evaluate 36x - y when x = 3 and y = -6

Given the expression

36x - y

substitute x = 3 and y = -6 to evaluate the expression

36x-y= 36(3) - (-6)

            = 108+6

            = 114

Therefore, the value of 36x - y when x = 3 and y = -6 will be: 114

5 0
2 years ago
2x-32=12<br> means they spent how much
Hoochie [10]

Answer:

22

Step-by-step explanation:

6 0
2 years ago
1. Determine if each of the following triangles is a right-angled triangle. For each right-angled triangle, state the right angl
Westkost [7]
You can use trigonometry specially the cos rule in this case. I can’t send the other pictures. But using the cos rule you can check whether the angle is 90

8 0
3 years ago
Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k
ch4aika [34]

Given

\vec v =  f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k

the curl of \vec v is

\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

7 0
3 years ago
Solve 12 + 6m = 2m. m = =​
Shkiper50 [21]

Answer:

-3

Step-by-step explanation:

8 0
2 years ago
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