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3 years ago

Pls help me and I’ll give brainliest to u and if u don’t know don’t answer and also don’t waste my points thx

Mathematics

2 answers:

alekssr [168]3 years ago

8 0

Answer:

-6a+35b+48c

Step-by-step explanation:

Katena32 [7]3 years ago

5 0

6a+35b+48c I think this is the correct answer

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Lauren has 108 pieces of candy leftover from Halloween. She would like to distribute them evenly to the 9 kids on her block. Wri

Pani-rosa [81]

Answer:

each kid gets 9 pieces

Step-by-step explanation:

5 0

3 years ago

The clock is set correctly at 1:00 pm . The clocks drops 1 minute every hour. When the correct time is 6:00 ,what time will the

PtichkaEL [24]

5:55

in 5 hours, it will have dropped 5 minutes.

6 0

3 years ago

Solve for y. log 5+log y=log 40 enter your answer in the box.

Vadim26 [7]

Answer:

The value of y for given log function is 8 .

Step-by-step explanation:

Given as :

The log function is Log 5 + Log y = Log 40

Or, Log y = Log 40 - Log 5 .........1

∵ From the Log property

Log m - Log n = Log $\dfrac{m}{n}$

So, Log 40 - Log 5 = Log $\dfrac{40}{5}$

Or, Log 40 - Log 5 = Log 8 .........2

Now, From eq 1 and 2

Log y = Log 8

∴ y = 8

So, The value of y = 8

Hence, The value of y for given log function is 8 . Answer

8 0

4 years ago

Emery earns money mowing his neighbors' lawns. He charges $1.25 per square yard for each lawn he mows. His neighbors, the Flores

aleksandr82 [10.1K]

Answer: 4.2 yards

Step-by-step explanation:

Let x = length of the Flores' lawn in yards.

Then, Area of lawn = 4x sq. yard [Area of rectangle = width x length , here width = 4 yds (given)]

Charge per square yard = $1.25

Charge for Flores lawn = 1.25 × (Area of lawn)

= 1.25 (4x)

= 5x

As per given,

$5x=21\\\\\Rightarrow\ x=\dfrac{21}{5}\\\\\Rightarrow\ x=4.2$

Hence, the length of the Flores's lawn = 4.2 yards

5 0

3 years ago

The third term of an arithmetical progression is 7, and the seventh term is 2 more than 3 times the third term.Find the first te

Sphinxa [80]

General formula for n-th term of arithmetical progression is

a(n)=a(1)+d(n-1).

For 3d term we have

a(3)=a(1) +d(3-1), where a(3)=7
7=a(1)+2d

For 7th term we have
a(7)=a(1) +d(7-1)
a(7)=a(1) + 6d

Also, we have that the seventh term is 2 more than 3 times the third term,
a(7)=3*a(3)+2= 3*7+2=21+2=23

So we have, a(7)=a(1) + 6d and a(7)=23. We can write
23=a(1) + 6d.

Now we can write a system of equations
23=a(1) + 6d
 - (7=a(1)+2d)
16 = 4d
d=4,

7=a(1)+2d

7=a(1)+2*4
a(1)=7-8=-1
a(1)= - 1

First term a(1)=-1, common difference d=4.

Sum of the 20 first terms is
S=20 * (a(1)+a(20))/2

a(1)=-1
a(n)=a(1)+d(n-1)
a(20) = -1+4(20-1)=-1+4*19=75

S=20 * (-1+75)/2=74*10=740

Sum of 20 first terms is 740.

3 0

3 years ago