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EleoNora [17]
3 years ago
15

Un muelle se alarga 30 centímetros cuando ejercemos sobre el una fuerza de 24 N a) calcula el valor de la constante elástica del

muelle b) calcula el alargamiento del muelle al aplicar una fuerza de 60 N
Physics
1 answer:
Artemon [7]3 years ago
3 0

Answer:

(a) k = 80 N/m   (b) x = 75 cm

Explanation:

The question says that, "A spring is elongated 30 centimeters when we exert a force of 24 N on it a) calculate the value of the spring constant b) calculate the elongation of the spring when applying a force of 60 N"

Given that,

Force exerted on the spring, F = 24 N

Elongation in the spring, k = 30 cm =0.3 m

(a) We know that, the force on the spring is given by :

F = kx

Where

k is spring constant

So,

k=\dfrac{F}{x}\\\\k=\dfrac{24}{0.3}\\\\k=80\ N/m

(b) When F = 60 N,

x=\dfrac{F}{k}\\\\x=\dfrac{60}{80}\\\\x=0.75\ m\\\\x=75\ cm

Hence, this is the required solution.

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<span>C. waves can only interfere destructively. </span>
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3 years ago
An air-filled pipe is found to have successive harmonics at 945 Hz , 1215 Hz , and 1485 Hz . It is unknown whether harmonics bel
Aleonysh [2.5K]

Answer:

L = 0.635m

Explanation:

This problem involves the concept of stationary waves in pipes. For pipes closed at one end,

The frequency f = nv/4L for n = 1,3,5....n

For pipes open at both ends

f = nv/2L for n = 1,2,3,4...n

Assuming the pipe is closed at one end and that velocity of sound is 343m/s in air. If we are right we will obtain a whole number for n.

The film solution can be found in the attachment below.

8 0
3 years ago
A ski gondola is connected to the top of a hill by a steel cable of length 620 m and diameter 1.5 cm. As the gondola comes to th
xz_007 [3.2K]

Answer:

(a) 89 m/s

(b) 11000 N

Explanation:

Note that answers are given to 2 significant figures which is what we have in the values in the question.

(a) Speed is given by the ratio of distance to time. In the question, the time given was the time it took the pulse to travel the length of the cable twice. Thus, the distance travelled is twice the length of the cable.

v=\dfrac{2\times 620 \text{ m}}{14\text{ s}} = \dfrac{1240\text{ m}}{14\text{ s}}=88.571428\ldots \text{ m/s}= 89\text{ m/s}

(b) The tension, T, is given by

v =\sqrt{\dfrac{T}{\mu}}

where v is the speed, T is the tension and \mu is the mass per unit length.

Hence,

T = \mu\cdot v^{2}

To determine \mu, we need to know the mass of the cable. We use the density formula:

\rho = \dfrac{m}{V}

where m is the mass and V is the volume.

m=\rho\cdot V

If the length is denoted by l, then

\mu = \dfrac{m}{l} = \dfrac{\rho\cdot V}{l}

T = \dfrac{\rho\cdot V}{l} v^{2}

The density of steel = 8050 kg/m3

The cable is approximately a cylinder with diameter 1.5 cm and length or height of 620 m. Its volume is

V = \pi \dfrac{d^{2}}{4} l

T = \dfrac{\rho\cdot\pi d^2 l}{4l}v^2 = \dfrac{\rho\cdot\pi d^2}{4}v^2

T = \dfrac{8050\times\pi\times0.015^2}{4} \times 88.57^2

T = 11159.4186\ldots \text{ N} = 11000 \text{ N}

4 0
4 years ago
Determine the acceleration that results when a 12 N net force is applied to a 3 kg object.
Vadim26 [7]

Heya!!

For calculate aceleration, let's applicate second law of Newton:

\boxed{F=ma}

⇒ Being:

→ F = Force = 12 N

→ m = Mass = 3 kg

→ a = aceleration = ?

Lets replace according formula and leave the "a" alone:

12\ N = 3\ kg * \textbf{a}

\textbf{a} = 12\ N / 3\ kg

\textbf{a} = 4\ m/s^{2}

Result:

The aceleration of the object is of <u>4 m/s²</u>

3 0
3 years ago
Disturbances inside Earth’s core cause earthquakes. The starting point of the disturbance is called the epicenter. Why does the
Natali [406]
The waves lose energy in the form of heat. The frequency of the waves continues to increase. Disturbances inside Earth's core cause earthquakes. The starting point of the disturbance is called the epicenter.

5 0
3 years ago
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