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lawyer [7]
3 years ago
9

A ball is tied to the end of a cable of negligible mass. The ball is spun in a circle with a radius 2.00 m making 0.700 revoluti

ons per second. What is the centripetal acceleration of the ball?
Physics
2 answers:
Pavlova-9 [17]3 years ago
8 0
Centripetal acceleration = (speed)²/(radius) .

We know the radius.  We have to find the speed.

Speed around a circle = (circumference) / (time to go around)

The circumference of the circle is  (2 π) (radius) = 4 π meters.

We don't exactly know the time to go around.
We know that the ball goes around 0.7 times/second.
Flip that over, and you have  time to go around = second/0.7 .

So now, the centripetal acceleration is

                                   (speed)²/(radius) .

                             =  (4π meters · 0.7/sec)² / (2 meters)

                             =  (4π · 0.7 / 2)    m/s²

                             =      about        4.4 m/s²
Ira Lisetskai [31]3 years ago
6 0
1) find speed (8.8 m/s)
2) find acceleration (38.7 m/s^2)
answer is about 38.7 m/s^2

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Explanation:

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H - 53.2 = \frac{1}{2} g (t-1)^2

H - 53.2 = \frac{1}{2} g (t^2-2t+1)

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H - (H - 53.2) =\frac{1}{2} gt^2- (\frac{1}{2} gt^2-gt+\frac{1}{2} g)

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3 years ago
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