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lawyer [7]
3 years ago
9

A ball is tied to the end of a cable of negligible mass. The ball is spun in a circle with a radius 2.00 m making 0.700 revoluti

ons per second. What is the centripetal acceleration of the ball?
Physics
2 answers:
Pavlova-9 [17]3 years ago
8 0
Centripetal acceleration = (speed)²/(radius) .

We know the radius.  We have to find the speed.

Speed around a circle = (circumference) / (time to go around)

The circumference of the circle is  (2 π) (radius) = 4 π meters.

We don't exactly know the time to go around.
We know that the ball goes around 0.7 times/second.
Flip that over, and you have  time to go around = second/0.7 .

So now, the centripetal acceleration is

                                   (speed)²/(radius) .

                             =  (4π meters · 0.7/sec)² / (2 meters)

                             =  (4π · 0.7 / 2)    m/s²

                             =      about        4.4 m/s²
Ira Lisetskai [31]3 years ago
6 0
1) find speed (8.8 m/s)
2) find acceleration (38.7 m/s^2)
answer is about 38.7 m/s^2

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Which of the following materials is brittle? wood metal ceramic plastic
Ira Lisetskai [31]
Ceramic is the most brittle of the materials you have specified. 

5 0
3 years ago
Oliver builds a circuit connecting a light bulb to a battery with wires, leaving a gap in one of the wires. He places several ob
Alexxandr [17]

Answer:

D. Electricity will flow if the electrons are bound loosely to their atoms in the material.

Explanation:

The continuous flow of charges is known as electricity (current). The flow of these charges are due to free or mobile electron within the atoms of the conductors. The materials which will allow current to pass through them, must have free or mobile electrons which are loosely bound to their atoms.

Thus, the correction for this question is "D"

D. Electricity will flow if the electrons are bound loosely to their atoms in the material.

6 0
3 years ago
Suppose you observed the equation for a traveling wave to be y(x, t) = A cos(kx − ????t), where its amplitude of oscillations wa
OLga [1]

Answer:

<h2>15m/s</h2>

Explanation:

The equation for a traveling wave as expressed as y(x, t) = A cos(kx − \omegat) where An is the amplitude f oscillation, \omega is the angular velocity and x is the horizontal displacement and y is the vertical displacement.

From the formula; k =\frac{2\pi x}{\lambda} \ and \ \omega = 2 \pi f where;

\lambda \ is\ the \ wavelength \ and\ f \ is\ the\ frequency

Before we can get the transverse speed, we need to get the frequency and the wavelength.

frequency = 1/period

Given period = 2/15 s

Frequency = \frac{1}{(2/15)}

frequency = 1 * 15/2

frequency f = 15/2 Hertz

Given wavelength \lambda = 2m

Transverse speed v = f \lambda

v = 15/2 * 2\\\\v = 30/2\\\\v = 15m/s

Hence, the transverse speed at that point is  15m/s

8 0
3 years ago
A baseball bat hits a baseball with a force of 100 newtons. What is the force and its direction exerted by the ball on the bat?
Brut [27]

Answer:

The force exerted by the ball on the bat has a magnitude of 100 N and its direction is exactly opposite to that of the force exerted by the bat on the ball.

Explanation:

Recall that Newton's third law tells us that : "For every action, there is an equal and opposite reaction."

Therefore if the bat acts on the ball with a force of 100 N, the ball acts on the bat with a similar magnitude of force (100 N) but direction opposite to the original force.

F_{ab} = -\,F_{ba}

7 0
3 years ago
Choose the law each sentence describes. This law relates a planet's orbital period and its average distance to the Sun. The orbi
hram777 [196]

These are the Kepler's laws of planetary motion.

This law relates a planet's orbital period and its average distance to the Sun. - Third law of Kepler.

The orbits of planets are ellipses with the Sun at one focus. - First law of Kepler.

The speed of a planet varies, such that a planet sweeps out an equal area in equal time frames. - Second law of Kepler.

7 0
3 years ago
Read 2 more answers
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