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3 years ago

How many favorable outcomes will there be for spinning the same color twice?

Mathematics

2 answers:

Tcecarenko [31]3 years ago

8 0

Answer:

3 favorable outcomes

There are three paths that end up with spinning the same color twice

natulia [17]3 years ago

5 0

Answer:

should be 3

Step-by-step explanation:

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Which equation represents a line parallel to the line shown on the graph?

FromTheMoon [43]

Answer:

Step-by-step explanation:

i took the test

7 0

3 years ago

Help with expressing a graph as an inequality ?

IRINA_888 [86]

Its been a little while, but im pretty sure it is y (greater than or equal to sign) 3/4x - 3

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3 years ago

Suppose the speeds of vehicles traveling on a highway are normally distributed and have a known population standard deviation of

ladessa [460]

Answer:

The margin of error for the confidence interval for the population mean with a 98% confidence level is 2.88 miles per hour.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.01 = 0.99$ , so $z = 2.326$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Find the margin of error for the confidence interval for the population mean with a 98% confidence level.

$M = 2.326*\frac{7}{\sqrt{32}} = 2.88$

The margin of error for the confidence interval for the population mean with a 98% confidence level is 2.88 miles per hour.

5 0

3 years ago

Is the following conditional true?<br> If x < 4, then x < 10<br> O yes<br> O no

Kay [80]

Answer: No, i think so.

7 0

1 year ago

In order to qualify for finals in racing event,a race car must achieve an average speed of 250km/hr on a track with a total leng

Kazeer [188]

Answer:

The minimum average speed needed in the second half is 270 km/hr

Step-by-step explanation

We can divide the track in two parts. For the first half of the track the average speed the car achieved was 230 km/hr and we need to make sure that the average speed of the full track is 250 km/hr. Then, we can calculate the average speed of the two parts of the track and force this to be equal to 250 km/hr. In equation, defining $v_2$ as the average speed of the second half:

$\frac{230 + v_2}{2}=250$

Solving for $x$

$x=250*2-230\\x=500-230\\x=270$

Therefore, achieving a speed of 270 km/hr in the second half would be enough to achieve an average speed of 250 on the track.

6 0

3 years ago