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Sergeeva-Olga [200]
3 years ago
10

The Centers for Disease Control and Prevention (CDC) define a healthy sleep duration to be at least seven hours per day. The CDC

reports that the percentage of people who report a healthy sleep duration varies by marital status. The CDC also reports that in 2018, 67% of those who are married report a healthy sleep duration; 62% of those who have never been married report a healthy sleep duration; and 56% of those who are divorced, widowed, or separated report a healthy sleep duration. The file SleepHabits contains sample data on the sleeping habits of people who have never been married that are consistent with the CDC's findings. Use these data to answer the following questions.
a. Develop a point estimate for the proportion of those who have never been married who report a healthy sleep duration.
b. Develop a point estimate for the mean number of hours of sleep for those who have never been married.
c. Develop a 95% confidence interval for the mean number of hours of sleep for those who have never been married.
Mathematics
1 answer:
Elza [17]3 years ago
4 0

Answer:

mmm

Step-by-step explanation:

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let's firstly convert the mixed fractions to improper fractions and then add up all four days.

\bf \stackrel{mixed}{16\frac{3}{4}}\implies \cfrac{16\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{67}{4}}~\hfill \stackrel{mixed}{12\frac{3}{4}}\implies \cfrac{12\cdot 4+3}{4}\implies \cfrac{47}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{all 4 days summed up}}{\cfrac{67}{4}+\cfrac{47}{4}}\implies \cfrac{67+47}{4}\implies \cfrac{114}{4}\implies \cfrac{57}{2}\implies 28\frac{1}{2}

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What is the binomial expansion of (x + 2y)7?
borishaifa [10]
<h2>Thus, the required "option 4)"  is correct.</h2>

Step-by-step explanation:

We find,

(x+2y)^7

To find, the binomial expansion of of (x+2y)^7 = ?

We know that,

(x+y)^{n} =^nC_0x^n+^nC_1x^{n-1}y+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+...+^nC_ny^n

∴ (x+2y)^7

Here, n = 7, x = x and y = 2y

(x+2y)^7= ^7C_0x^7+^7C_1x^{7-1}(2y)+^7C_2x^{7-2}(2y)^2+^7C_3x^{7-3}(2y)^3+^7C_4x^{7-4}(2y)^4+^7C_5x^{7-5}(2y)^5+^7C_6x(2y)^6+(2y)^7=x^7+7x^{6(2y)+21x^{5}4y^2+35x^{4}8y^3+^35x^{3}16y^4+21x^{2}32y^5+7x64y^6+128y^7

=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7

∴ The binomial expansion of of (x+2y)^7

=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7

Thus, the required "option 4)"  is correct.

7 0
3 years ago
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