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Arlecino [84]
2 years ago
6

Write 24 minutes to 3 hours as a ratio in its simplest form

Mathematics
2 answers:
Basile [38]2 years ago
8 0

3 hours  = 180 minutes

So, 24:180.

Simplified: 1:5

Hope this helps; have a great day!

SVEN [57.7K]2 years ago
6 0
3 / 60 = 180

24:180

6:45

3:15

1:5
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Distribute 8[(x + (-3)]​
Lemur [1.5K]

Answer:

8x-24

Step-by-step explanation:

8(x-3)

8 times x= 8x

8 times-3= -24

8 0
3 years ago
Quadratic equation please help
Andre45 [30]

Answer:

x= -3+√2 or x= -3-√2   ( answer : A  and B )

Step-by-step explanation:

hello :

x²+6x+9 = (x+3)².....identity

x²+6x+9 =2  means : (x+3)²=2

so : (x+3 = √2) or  (x+3 = - √2)

so two solutions :

x= -3+√2 or x= -3-√2

7 0
3 years ago
You randomly pick two numbers from 1 to 9 (including 1 and 9). A number that is chosen once could be chosen again. If at least o
Mnenie [13.5K]
Assume that you only include whole numbers (1,2,3,4,5,6,7,8,9) and not 3.5 and such
so if 1 is odd and less than 5 then it is
1 or 3, since 5 isn't included
then the other number, to be less than 5 when added,
must be
1+x<5
3+x<5
solve each
1+x<5
subtract 1
x<4
set of answers are 1,2,3

3+x<5
subtract 3
x<2
set of answer is 1
so the possible numbers are
1,2,3
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disred outcomes=3
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7 0
3 years ago
Please help, I'm so confused! I will give brainliest!
nika2105 [10]

Hello,


1) Vertical

2) Supplementary

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4) Alternate exterior


Hope it helps!

3 0
3 years ago
We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure
STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be h(t) = -16\cdot t^{2} + 128\cdot t + 320, the first and second derivatives are, respectively:

First Derivative

h'(t) = -32\cdot t +128

Second Derivative

h''(t) = -32

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

-32\cdot t +128 = 0

t = \frac{128}{32}\,s

t = 4\,s (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320

h(4\,s) = 576\,ft

The highest altitude that the object reaches is 576 feet.

6 0
3 years ago
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