A) The greatest rectangular area will be the area of a square 10 m on each side, 100 m^2.
b) The new dimensions will be 11 m × 11 m.
.. The new area will be (11 m)^2 = 121 m^2.
c) The area was increased by 121 m^2 -100 m^2 = 21 m^2, or 21%.
d) Yes, and no.
.. If you increase the dimensions by 10%, the area will increase by 21%.
.. (40 m)^2 = 1600 m^2
.. (44 m)^2 = 1936 m^2 = 1.21*(1600 m^2), an increase of 21% over the original.
.. If you increase the dimensions by 1 unit, the area will increase by (2x+1) square units, where x is the side of the original. For x≠10, this is not 21 square units.
.. (41 m)^2 = 1681 m^2 = 1600 m^2 +(2*40 +1) m^2 = 1600 m^2 +81 m^2
Answer:
1152 inches of fringe
Step-by-step explanation:
l multiplies with width to get the area so
w is one half of 48 which 24
so 24x48 which is 1152 inches of fringe
Answer:
20%
Step-by-step explanation:
20 * 20% = 4
or you can change it to a decimal
20 * .2 = 4
hope this helped! :)
Answer:
H
Step-by-step explanation:
The parallel line BC divides the sides AD and AE in proportion, that is
= 
, that is
= 
( cross- multiply )
3AC = 8 ( divide both sides by 3 )
AC = 
= 2 , hence
AE = AC + CE
= 2 + 4 = 6 → H
