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Alja [10]
3 years ago
10

you pick a number between 1,000 and 5,000 then you flip a coin identify if the two events are independent or dependent explain

Mathematics
2 answers:
Lelu [443]3 years ago
7 0
Independent one has nothing to with the other

Mariana [72]3 years ago
6 0

Answer with Step-by-step explanation:

Events A and B are said to be independent if:

P(A∩B)=P(A)×P(B)

A:Picking a number between 1000 and 5000

B:flipping a coin

P(A)=1/4001

P(B)=1

P(A∩B)=1/4001

           =P(A)×P(B)

Hence, the two events are independent

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Consider the differential equation:
Wewaii [24]

(a) Take the Laplace transform of both sides:

2y''(t)+ty'(t)-2y(t)=14

\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s

where the transform of ty'(t) comes from

L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)

This yields the linear ODE,

-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s

Divides both sides by -s:

Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}

Find the integrating factor:

\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C

Multiply both sides of the ODE by e^{3\ln|s|-s^2}=s^3e^{-s^2}:

s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}

The left side condenses into the derivative of a product:

\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}

Integrate both sides and solve for Y(s):

s^3e^{-s^2}Y(s)=7e^{-s^2}+C

Y(s)=\dfrac{7+Ce^{s^2}}{s^3}

(b) Taking the inverse transform of both sides gives

y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that \frac{7t^2}2 is one solution to the original ODE.

y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7

Substitute these into the ODE to see everything checks out:

2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14

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3 years ago
The measure of an angle is 60° less than nineteen times the measure of its supplement. what is the measure of the angle?
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x = angle
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x + 19x - 60 = 180
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x = 12</span>°  ← answer
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Plsssss help before it gets locked
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A. Is answer F

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