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3 years ago

you pick a number between 1,000 and 5,000 then you flip a coin identify if the two events are independent or dependent explain

Mathematics

2 answers:

Lelu [443]3 years ago

7 0

Independent one has nothing to with the other

Mariana [72]3 years ago

6 0

Answer with Step-by-step explanation:

Events A and B are said to be independent if:

P(A∩B)=P(A)×P(B)

A:Picking a number between 1000 and 5000

B:flipping a coin

P(A)=1/4001

P(B)=1

P(A∩B)=1/4001

=P(A)×P(B)

Hence, the two events are independent

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What is the value of x? There is isosceles triangle. The measure of angle which is between two congruent sides is (6x+10⁰). The

max2010maxim [7]

<h3><u>Answer</u><u>:</u><u>-</u></h3>

x=17

<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

${\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}$

<h3 />

This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Given angles

(6x+10°)
(x+17°)
(4x-34)°

According to sum theory

${\boxed{\sf The \:sum\:of\:angles=180°}}$

Substitute the values

$\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180$

Remove brackets

$\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180$

Together like polynomials and constants

$\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180$

$\qquad \quad{:}\longmapsto\tt 11x-7=180$

Interchange sides

$\qquad \quad{:}\longmapsto\tt 11x=180+7$

$\qquad \quad{:}\longmapsto\tt 11x=187$

$\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}$

Simplify

$\qquad \quad{:}\longmapsto\tt x=17$

$\therefore\sf The \:value\:of\:x\;is\:17.$

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2 years ago

Use summation notation to write the series 49 + 54 + 59 +... for 14 terms.

My name is Ann [436]

Answer:

Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.

it is given by: $a_n = a+(n-1)d$ where a is the first term , n is the number of term and d is the common difference.

Given the series: $49 + 54 + 59+ ......$

here, Common difference(d) = 5

First term(a) = 49

by definition we have;

For nth term

$a_n = a+(n-1)d$

$a_n = 49+(n-1)5$

$a_n =49+5n -5$ = 5n + 44

To write the series using summation notation for 14 terms

Summation symbol $'\sum'$

The series for 14th terms is given by;

$\sum_{n=1}^{14}(5n +44)$

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