15% * 8 cups
= 0.15 * 8 cups
= 1.2 cups
Answer:$11.5
Step-by-step explanation:
Admission = $9 charged once
each ride = $2.5x (x=number of rides)
Total cost for x rides
=2.5x+9
This is a simple equation.
The equation is y = 1.6x with y being the miles and x being the kilometers.
Lets plug the kilometers in.
Y=1.6(7.7)
1.6 * 7.7 = 12.32
12.32 miles is equal to 7.7 kilometers
HOWEVER
There are about .6 miles in a kilometer, so if you typed this wrong I don't know.
It is still the same concept.
Y = .6x
Y = .6(7.7)
.6 * 7.7 = 4.8
In this case there are 4.8 miles in 7.7 kilometers
<em>Greetings from Brasil...</em>
In a trigonometric function
F(X) = ±UD ± A.COS(Px + LR)
UD - move the graph to Up or Down (+ = up | - = down)
A - amplitude
P - period (period = 2π/P)
LR - move the graph to Left or Right (+ = left | - = right)
So:
A) F(X) = COS(X + 1)
standard cosine graph with 1 unit shift to the left
B) F(X) = COS(X) - 1 = -1 + COS(X)
standard cosine graph with 1 unit down
C) F(X) = COS(X - 1)
standard cosine graph with shift 1 unit to the right
D) F(X) = SEN(X - 1)
standard Sine graph with shift 1 unit to the right
Observing the graph we notice the sine function shifted 1 unit to the right, then
<h3>Option D</h3>
<em>(cosine star the curve in X and Y = zero. sine start the curve in Y = 1)</em>
<u>Answer:</u>
Cost of package of paper = 4$
Cost of stapler = 7$
<u>Explanation:</u>
Consider the cost of package of paper = x and that of stapler = y.
Now, we are given that cost of 3 paper packages and 4 staplers = 40$
Hence we get, 3x + 4y = 40 as 1st equation.
we are also given, cost of 5 paper packages and 6 staplers = 62$
Hence, the second equation is 5x + 6y = 62
Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->
15x + 20y = 200
15x + 18y= 186
Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4
which gives the required cost of one paper package = x = 4$
and one stapler = y = 7$