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irinina [24]
3 years ago
10

How do you solve for y?

Mathematics
1 answer:
Alchen [17]3 years ago
5 0
To find 'y', you must get it by itself in the equation. In order to do so, you need to get rid of other values on that side of the equation, while still making the expression equal the same. You need to "balance the equation". To do so, subtract 2 from both sides of the equation.

y + 2 = x
   - 2    -2
y = x - 2

Your simplest answer for this problem would be y = x - 2

Hope this helps!
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Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

5 0
2 years ago
The question is evaluate x÷1.2 for each value of x         x=40.8
Aleks [24]
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4 0
3 years ago
The digit 1 in which number represents a value of 10,000
nika2105 [10]
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3 0
3 years ago
Read 2 more answers
Find the value of x.
nadezda [96]

Answer:

25

Step-by-step explanation:

The median of a trapezoid equals one half of the sum of the bases

AC is a median and EB and DF are the bases.

hence AC = 1/2(EB + DF)

We are given that EB = 13 and that AC = 19. And we need to find DF

To do so we plug in what we are given and solve for DF

AC = 1/2(EB + DF)

AC = 19, EB = 13

19 = 1/2(13 + DF)

Now solve for DF

* Multiply both sides by 2*

19 * 2 = 38

1/2(13 + DF) * 2 ( the 1/2 and 2 cancel out and we're left with 13 + DF )

We then have 38 = 13 + DF

* Subtract 13 from both sides *

38 - 13 = 13 - 13 + DF

We get that DF = 25

6 0
3 years ago
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elena55 [62]

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HOPE IT HELPS

PLEASE MARK ME BRAINLIEST ☺️

7 0
3 years ago
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