Answer:
3
Step-by-step explanation:
Your answer is 3
Answer:
29 is answer.
Step-by-step explanation:
Given that the function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237.
To find average velocity of the object over the interval of time [1,3]
We know that derivative of s is velocity and antiderivative of velocity is position vector .
Since moving along a line equation of s is
use two point formula
gives the position at time t.
Average velocity in interval (1,3)
=![\frac{1}{3-1} (s(3)-s(1))\\=\frac{1}{2} [87+58-29-58]\\=29](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3-1%7D%20%28s%283%29-s%281%29%29%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%20%5B87%2B58-29-58%5D%5C%5C%3D29)
Answer:
x = X + 33 (I am guessing "x" and "X" are not the same. "x" is a variable and "X" is a constant.)
Step-by-step explanation:
31 - X + (2x+1) = x - 1
or, 2x+1 = x - 1 - 31 + X
or, 2x - x = -1 -31 + X -1
or, x = -2 -31 + X
or, x = X - 33
y = 0.012x + 0.65<span><span><span>
Number of pages </span>
<span> 50.00 </span><span> 100.00 </span><span> 150.00 </span>
<span> 200.00 </span>
</span>
<span>
<span>
Cost </span>
<span> 1.25 </span>
<span> 1.85 </span>
<span> 2.45 </span>
<span> 3.05
x = number of pages
y = cost
intervals of x = 50 pages
intervals of y = 0.60
0.60 / 50 = 0.012
y = 0.012x + 0.65
</span></span></span><span>
<span>
</span><span><span>
<span> x </span>
<span> 0.012*x </span>
<span> y </span>
</span>
<span>
0.012
<span> 50 </span>
<span> 0.60 </span>
<span> 0.65 </span>
<span> 1.25
</span></span><span>0.012
<span> 100 </span>
<span> 1.20 </span>
<span> 0.65 </span>
<span> 1.85
</span>
</span>
<span>
0.012
<span> 150 </span>
<span> 1.80 </span>
<span> 0.65 </span>
<span> 2.45
</span>
</span>
<span>
0.012
<span> 200 </span>
<span> 2.40 </span>
<span> 0.65 </span>
<span> 3.05 </span>
</span></span></span><span>
</span>
Answer:
20.8
Step-by-step explanation:
hope this helps
