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taurus [48]
3 years ago
5

Given sin A=-√3/2 and tan A >0, find cos A. PLEASE HURRY AND SHOW WORK

Mathematics
1 answer:
shutvik [7]3 years ago
4 0

Answer:

Below in bold.

Step-by-step explanation:

We have a right triangle here with the hypotenuse = 2 and the legs are 1 and √3.

If tan A > 0 then the opposite side to < A  in the triangle is greater than the adjacent so the leg opposite angle A is √3 and the adjacent side = 1.

So cos A = adj/hyp = 1/2.

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Can someone help me out please, thank you.
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Here are a few rules about exponents you should know:

  1. Multiplying exponents of the same base: x^m*x^n=x^{m+n}
  2. Dividing exponents of the same base: \frac{x^m}{x^n}=x^{m-n}
  3. Powering a power to a power: (x^m)^n=x^{m*n}
  4. Converting a negative exponent into a positive one: x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m

Firstly, multiply the y bases: \frac{z^5}{(-y^{-4}y^{-1}x^3)^{-3}}=\frac{z^5}{(-y^{-4+-1}x^3)^{-3}}=\frac{z^5}{(-y^{-5}x^3)^{-3}}

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