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hichkok12 [17]
3 years ago
10

A man attempts to push his couch to the left. The man is too weak and the couch does not move. Does the man exert a force on the

couch?
Select one:
a. No because the couch did not move.
b. Not enough information to determine.
c. No because the man did not pull the couch.
d. Yes because the man pushed on the couch while other forces caused the couch to not nove mu​
Physics
1 answer:
Daniel [21]3 years ago
6 0

Answer:

b or d I can't decide but if one of those

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Answer:

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Explanation:

See the attached file for the masses distributions

The force between two masses at distance r is expressed as

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since the masses are of the same value, the above formula can be reduce to

F=\frac{Gm^{2}}{r^{2} }\\

using vector notation,Let use consider the force on the lower left corner of the mass due to the upper left side of the mass is

F_{12} =\frac{Gm^{2}}{r^{2} }j\\

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F_{13} =\frac{Gm^{2}}{d^{2} }cos\alpha i +\frac{Gm^{2}}{d^{2} }sin\alpha j\\

The net force can be express as

F=\frac{Gm^{2}}{r^{2} }j +\frac{Gm^{2}}{r^{2} }i +\frac{Gm^{2}}{d^{2} }cos\alpha i +\frac{Gm^{2}}{d^{2} }sin\alpha j\\\\F=Gm^{2}[\frac{1}{r^{2}}+ \frac{1}{d^{2}cos\alpha }]i + Gm^{2}[\frac{1}{r^{2}}+ \frac{1}{d^{2}sin\alpha }]j\\\alpha=45^{0}, G=6.67*10^{-11}Nmkg^{-2}

if we insert values we arrive at

F=6.67*10^{-11}*2.5^{2}[\frac{1}{1^{2}}+ \frac{1}{\sqrt{2}^{2}cos45 }]i + 6.67*10^{-11}*2.5^{2}[\frac{1}{1^{2}}+ \frac{1}{\sqrt{2}^{2}sin45}]j\\F=5.643*10^{-10}i+5.643*10^{-10}j

if we solve for the magnitude, we arrive at

F=5.643*10^{-10}i+5.643*10^{-10}j \\F=\sqrt{(5.643*10^{-10})^{2} +(5.643*10^{-10})}^{2} \\F=8.0*10^{-10}

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Answer:

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V_{wf} = \frac{m_{b}V_{bi} - m_{b} V_{bf}    }{m_{W} }

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V = \frac{m_{b} }{m_{b}+m_{w} } V_{bi}

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V = \frac{5.3(g)}{5.3(g)+610(g)} X 963(m/s)

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