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andriy [413]
3 years ago
6

How long would it take a rolling can to accelerate from 16 m/s to 24 m/s with an acceleration of 4m/s2? (Which equation would I

use?)

Physics
2 answers:
SIZIF [17.4K]3 years ago
7 0

Answer:

answer is option 3

Explanation:

because you need to find out time

Olegator [25]3 years ago
3 0

Answer:

Option 3

Explanation:

Since we are solving for time, the time should be by itself on a side.

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3. A cat pushes a 0.25-kg toy with a net force of 8 N. According to Newton's second
jek_recluse [69]
  • Mass=0.25kg
  • Force=8N

\\ \sf{:}\!\implies F=ma

\\ \sf{:}\!\implies Acceleration=\dfrac{F}{m}

\\ \sf{:}\!\implies Acceleration=\dfrac{8}{0.25}

\\ \sf{:}\!\implies Acceleration=32m/s^2

5 0
3 years ago
The number line shows the starting and ending velocities for ball 1. What’s the change in velocity of ball 1? Calculate the valu
djverab [1.8K]

Answer:

The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.

The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds

5 0
3 years ago
Read 2 more answers
How can the atomic number of nitrogen be determined?
Doss [256]

Answer:

So... for the element of NITROGEN, you already know that the atomic number tells you the number of electrons. That means there are 7 electrons in a nitrogen atom. Looking at the picture, you can see there are two electrons in shell one and five in shell two.

4 0
3 years ago
Can someone please help, ty!!<br> Will mark brainliest.
Vinil7 [7]

Answer:

#1 ( Balanced ) ( Rest)

#2 ( Unbalanced)  ( Accelerating)

Explanation:

3 0
3 years ago
A 2,537-kg truck moving at 14 m/s strikes a car waiting at a traffic light, hooking bumpers. The two continue to move together a
slavikrds [6]

Answer:

1902.75 kg

Explanation:

From Law of conservation of momentum,

m₁u₁ + m₂u₂ = V (m₁ + m₂).................... Equation 1

make m₂ the subject of the equation,

m₂ = (m₁V - m₁u₁)/(u₂-V)..................... Equation 2

Where m₁ = mass of the truck, m₂ = mass of the car, u₁ initial velocity of the truck, u₂ = initial velocity of the car V = common velocity

Given: m₁ = 2537 kg, u₁ = 14, V= 8 m/s, u₂ = 0 m/s ( as the car was at rest waiting at a traffic light)

Substituting into equation 2.

m₂ =[2537(8) - 2537(14)]/(0-8)

m₂ = (20296-35518)/-8

m₂ = -15222/-8

m₂ = 1902.75 kg.

Thus the mass of the car = 1902.75 kg

5 0
4 years ago
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