Answer:
<em><u>Given: </u></em>
m1 = 7 kg
V1 = 12 m/s
m2 = 25 kg
V2 = 6 m/s
<em><u>To find:</u></em>
Combined speed of two balls stick together after collision V = ?
<em><u>Solution:</u></em>
<em>According to law of conservation of momentum,</em>
m1V1 + m2V2 = (m1+m2)V
7×12 + 25×6 = (7+25)V
84 + 150 = 32V
V = 234/32
V = 7.31 m/s
Combined speed of two ball is 7.31 m/s
<em><u>Thanks for joining brainly community!</u></em>
T<span>he </span>similarities between compounds<span> and </span>mixtures<span> are that they are both made up of two or more </span>elements<span> and that they could both be separated and then mixed with different </span>elements<span> to make a new </span>mixture<span> and </span>compound<span>.
</span>
Answer:
a) 3.7 m/s^2
b) 231.8 N
Explanation:
Let m1 be mass of the first object (m1 = 38.0 kg) and let m2 be the mass of the second object (m2 = 17.0 kg ). Let a be the acceleration of the two objects. Let F1 be the force of gravity exerted on m1 and F2 be the force of gravity exerted on m2. Let M = m1 +m2
a)
F1 = m1g and F2 = m2g
So Fnet = F1 + F2
Since the pulleys will move in different directions when accelerating...
Fnet = F1 - F2
M×a = m1g - mg2
M×a = g×(m1 -m2)
a = g×(m1 - m2)/M
a = 9.8×(38 - 17)/(38 + 17)
a = 3.7 m/s^2
b)
Looking at the part for m2
Fnet = T - m2g
-m2×a = T - m2g
T = m2(g - a)
T = 231.8 N
Answer:
B
Explanation:
acceleration = change in speed / change in time
for 1, speed increases over time, so positive acceleration
for 3, speed decreases over time, so negative acceleration (or deceleration)
Two waves interfere when they run into each other.
The barrier reflects waves that run straight into it. It acts as a wave source and sends wave pulses back up the page towards the incoming waves.
Imagine a loose string tied to a wall. Someone sends two consecutive pulses along the string towards the wall. The first pulse gets reflected right away. It will travel backward towards the person holding the string. Along its way, it will run into the second pulse. The two pulses will interfere. The wall will make the reflected pulse out of phase with the second one. They will end up creating a destructive interference.
So is the case with the water waves running into the barrier. The barrier will send incoming waves back toward where they came from. Reflected waves interfere with incoming ones.