Answer:
mdmfnndhhdhdnd brnrnhruh hehrbfb hfnfnfbj bdnbdhdh hxhhn ndnnjnxnamkdjjfjfjjdjz hzjsuklshhwhhhèushhhhhdhhhshdùunvcn n nn nn nn n b ncjjnndnhshsb bsbbdnnnns nndnfnkkdgdhp1 gyduia
You HAVE to use Pemdas.
2[3(4^2+1)]-2^3
2(3(16+1))-2^3
2(3(17))-2^3
2*51-2^3
102-8
94.
Explanation: you use Pemdas P-parenthesis
E-exponents
M-multiplication
D-division
A-addition
S-subtraction
Answer:
Factor this polynomial:
F(x)=x^3-x^2-4x+4
Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3).
The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you find that the roots are at
x = 1, x = 2 and x = -2. This means that
x^3-x^2-4x+4 = A(x - 1)(x - 2)(x + 2)
A = 1, as you can see from equation the coefficient of x^3 on both sides.
Typo:
The rational roots can be
+/-1, +/-2 and +/-4
Step-by-step explanation:
9h < -79 - 2
9h < -81
h < -81/9
h < -9
