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3 years ago

Translate quadrilateral ABCD 5 units to the right and 6 units down.

Mathematics

1 answer:

dezoksy [38]3 years ago

6 0

Answer:

D. A'(1,-7), B'(2,-1), C'8,-2) and D'(7,-5)

Step-by-step explanation:

Probably too late, but I took the quiz

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There is a 33.3% chance of rolling a number less than 6. It’s 2/6, which is reduced to 1/3. = that to x/100, multiply 1 x 100, and divide that by 3. So it’s 100 divided by 3, and that’s 33.3, which is the percentage.

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3 years ago

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Can you help meSolve for X pretty please 4+x=7

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use a calculator / solve for x calculator

Step-by-step explanation:

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Directions: Complete each proof using the properties of equality. Not all rows be used.

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3 years ago

A candle in the shape of a circular cone has a base of radius r and a height of h that is the same length as the radius. which e

ladessa [460]

Answer:

$\frac{r(1-\sqrt{2})}{-3}$

Step-by-step explanation:

Volume of cone = $\frac{1}{3} \pi r^{2} h$

Since we are given that a circular cone has a base of radius r and a height of h that is the same length as the radius

= $\frac{1}{3} \pi r^{2} \times r$

= $\frac{1}{3} \pi r^{3}$

Surface area of cone including 1 base = $\pi r^{2} +\pi\times r \times \sqrt{r^2+h^2}$

Since r = h

So, area = $\pi r^{2} +\pi\times r \times \sqrt{r^2+r^2}$

= $\pi r^{2} +\pi\times r \times \sqrt{2r^2}$

= $\pi r^{2} +\pi\times r^2 \times \sqrt{2}$

Ratio of volume of cone to its surface area including base :

$\frac{\frac{1}{3} \pi r^{3}}{\pi r^{2} +\pi\times r^2 \times \sqrt{2}}$

$\frac{\frac{1}{3}r}{1+\sqrt{2}}$

$\frac{r}{3(1+\sqrt{2})}$

Rationalizing

$\frac{r}{3(1+\sqrt{2})} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}$

$\frac{r(1-\sqrt{2})}{-3}$

Hence the ratio the ratio of the volume of the candle to its surface area(including the base) is $\frac{r(1-\sqrt{2})}{-3}$

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3 years ago

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GarryVolchara [31]

Answer:

1/6, because there is only one way it's possible and there are 6 outcomes.

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