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IgorC [24]
3 years ago
14

runnin reggie ran up a mountain from an elevation of 915 m to 4095 m in 62.25 min. If Reggie has a mass of 70 kg, how much power

did Reggie generate during his run?
Physics
1 answer:
Stella [2.4K]3 years ago
3 0

Answer:

....................

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Ernie speed walks at the rate of 20m/s in 5 seconds. Calculate the distance he traveled
taurus [48]

Answer:

4m

Explanation:

you divide 20m/s by 5 seconds

7 0
3 years ago
If there are 6 coulombs of charge moving through a wire in 2 seconds. How many amps are moving through this wire?
Lelechka [254]

Answer:

Current = 3 Amperes

Explanation:

Given the following data;

Quantity of charge = 6 C

Time = 2 seconds

To find how many amps are moving through this wire;

Mathematically, the quantity of charge passing through a conductor is given by the formula;

Quantity of charge = current * time

Substituting into the formula, we have;

6 = current * 2

Current = 6/2

Current = 3 Amperes

6 0
3 years ago
The density of Mercury is 1.36 × 10 by 4 Kgm - 3 at 0 degrees. Calculate its value at 100 degrees and at 22 degrees. Take cubic
Drupady [299]

a) Density at 100 degrees: 1.34\cdot 10^4 kg/m^3

Explanation:

The density of mercury at 0 degrees is d=1.36\cdot 10^4 kg/m^3

Let's take 1 kg of mercury. Its volume at 0 degrees is

V=\frac{m}{d}=\frac{1 kg}{1.36\cdot 10^4 kg/m^3}=7.35\cdot 10^{-5} m^3

The formula to calculate the volumetric expansion of the mercury is:

\Delta V= \alpha V \Delta T

where

\alpha=180\cdot 10^{-6} K^{-1} is the cubic expansivity of mercury

V is the initial volume

\Delta T is the increase in temperature

In this part of the problem, \Delta T=100 C-0 C=100 C=100 K

So, the expansion is

\Delta V= \alpha V \Delta T=(180\cdot 10^{-6} K^{-1})(7.35\cdot 10^{-5} m^3)(100 K)=1.3\cdot 10^{-6} m^3

So, the new density is

d'=\frac{m}{V+\Delta V}=\frac{1 kg}{7.35\cdot 10^{-5} m^3+1.3\cdot 10^{-6} m^3}=1.34\cdot 10^4 kg/m^3


b) Density at 22 degrees: 1.355\cdot 10^4 kg/m^3

We can apply the same formula we used before, the only difference here is that the increase in temperature is

\Delta T=22 C-0 C=22 C=22 K

And the volumetric expansion is

\Delta V= \alpha V \Delta T=(180\cdot 10^{-6} K^{-1})(7.35\cdot 10^{-5} m^3)(22 K)=2.9\cdot 10^{-7} m^3

So, the new density is

d'=\frac{m}{V+\Delta V}=\frac{1 kg}{7.35\cdot 10^{-5} m^3+2.9\cdot 10^{-7} m^3}=1.355\cdot 10^4 kg/m^3


8 0
3 years ago
A tennis ball of mass m=0.060 kg and speed v=25 m/s strikes a wall at a 45 angle and rebounds with the same velocity at 45°. Wha
Diano4ka-milaya [45]

To solve this problem we will apply the concepts related to the Impulse which can be defined as the product between mass and the total change in velocity. That is to say

p = m\Delta v

Here,

m = mass

\Delta v = Change in velocity

As we can see there are two types of velocity at the moment the object makes the impact,

the first would be the initial velocity perpendicular to the wall and the final velocity perpendicular to the wall.

That is to say,

v_i = vcos\theta

v_f = -v sin\theta

El angulo dado es de 45° y la velocidad de 25, por tanto

v_i = (25)cos(45) = 17.68m/s

v_f = -(25)sin(45) = -17.68m/s

The change of sign indicates a change in the direction of the object.

Therefore the impulse would be as

p = 0.060(-17.68-17.68)

p = -2.12kg \cdot m/s

The negative sign indicates that the pulse is in the opposite direction of the initial velocity.

3 0
3 years ago
Stars are powered by _____ reactions.
siniylev [52]
They are powered by fusion reactions
3 0
3 years ago
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