All categories

3 years ago

Is an object speeding up or slowing down of the V final is greater than the V initial?

Physics

1 answer:

sertanlavr [38]3 years ago

7 0

Answer:

V is greater

Explanation:

because v intial at that time V final is the that speed which it is going at that time

You might be interested in

Which location would the selected items BEST fit on the nuclear energy diagram?

Sladkaya [172]

Your answer is c) Fusion

7 0

4 years ago

Read 2 more answers

If a neutral material like fur is rubbed on another neutral object like a rubber ball what is the resulting charges of the objec

alexdok [17]

Answer:

Explanation:

they both have a neutral charge so they couldn't be positive or negative since that wouldn't come from anywhere

8 0

3 years ago

Contrast the force of gravity between these pairs of objects a 1 kg mass and a 2 kg mass that are 1 m apart and two 2 kg masses

Yuki888 [10]

Solution

Force between pair of objects of masses 1kg and 2kg that are 1m apart is given as

$F=G\times \frac{1\times 2}{1^2}$

here G is gravitational constant

G= $6.674\times10^{-11}Nm^2kg^{-2}$

therefore,

$F=6.674\times10^{-11}Nm^2kg^{-2}\times 2$

$F=13.348\times10^{-11}Nm^2kg^{-2}$

similarly Force between pair of objects of masses 2kg each that are 1m apart is given as

$F'=G\times \frac{2\times 2}{1^2}$

$F'=6.674\times10^{-11}Nm^2kg^{-2}\times 4$

$F'=2\times 13.348\times10^{-11}Nm^2kg^{-2}$

or F'=2F

it means Force between pair of objects of masses 2kg each that are 1m apart is equal to twice the Force between pair of objects of masses 1kg and 2kg that are 1m

7 0

3 years ago

A 0.106-A current is charging a capacitor that has square plates 4.60 cm on each side. The plate separation is 4.00 mm.

nikdorinn [45]

Answer:

$\frac{d \phi_{E}}{dt} =1.1977 *10^{10} \ V\cdot m/s$

$I = 0.106 \ A$

Explanation:

From the question we are told that

The current is $I = 0.106 \ A$

The length of one side of the square $a = 4.60 \ cm = 0.046 \ m$

The separation between the plate is $d = 4.0 mm = 0.004 \ m$

Generally electric flux is mathematically represented as

$\phi_E = \frac{Q}{\epsilon_o}$

differentiating both sides with respect to t is

$\frac{d \phi_{E}}{dt} = \frac{1}{\epsilon_o} * \frac{d Q}{ dt}$

=> $\frac{d \phi_{E}}{dt} = \frac{1}{\epsilon_o} *I$

Here $\epsilon_o$ is the permitivity of free space with value

$\epsilon _o = 8.85*10^{-12} C/(V \cdot m)$

=> $\frac{d \phi_{E}}{dt} = \frac{0.106}{8.85*10^{-12}}$

=> $\frac{d \phi_{E}}{dt} =1.1977 *10^{10} \ V\cdot m/s$

Generally the displacement current between the plates in A

$I = 8.85*10^{-12} * 1.1977 *10^{10}$

=> $I = 0.106 \ A$

3 0

3 years ago

Estimate the order of magnitude of the length in meters of each of the following: a. a ladybug b. your leg c. your school buildi

sukhopar [10]

The order of the magnitude of the length in meters is estimated based on the average length of the object: if it is a small object then the unit would be cm and if it is a long object (like a road or something) the distance can be measured in km. Then we convert the unit we measured in into the SI unit of the meter.

Based on this, for the mentioned objects, the estimated length would be as follows:
a- ladybug: 10^-2 meters
b- your leg : 10^0 meters
c- your school building : 10^1 to 10^2 meters
d- a giraffe: 10^0 meters
e- city block: 10^2 meters

4 0

3 years ago