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Lisa [10]
3 years ago
12

For what values of b will F(x) = logbx be a decreasing function?

Mathematics
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

It is a decreasing function for 0 < b < 1.

Step-by-step explanation:

Logarithm function:

The logarithm function is given by:

F(x) = \log_{b}{(x)}

The base b determines if the function increases or decreases.

For 0 < b < 1, the function decreases.

For b > 1, the function increases.

In this question:

By the definition above, it is a decreasing function for 0 < b < 1.

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\displaystyle (x + 3)(x +3) = 49 \\ x^2+3x+3x+9=49 \\ x^2 +6x+9=49 \\ x^2 + 6x + 9 - 49 = 0 \\x^2+6x-40=0 \\\\ \Delta=b^2-4ac \\ \Delta=6^2-4 \cdot 1 \cdot (-40) \\ \Delta=36+160 \\ \Delta=196 \\ \\ X_{1,2}=\frac{-b \pm \sqrt{\Delta} }{2a}  \\ \\ X_1=\frac{-b+\sqrt{\Delta} }{2a} = \frac{-6+14}{2} = \frac{8}{2}=4 \\ \\ X_2=\frac{-b-\sqrt{\Delta} }{2a}  = \frac{-6-14}{2}=\frac{-20}{2} = -10

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